B: use a hammer with a longer handle, i just had that question
Answer:
Option A is correct
The electric potential at P1 is greater than that at P2, because r is smaller than 2r.
Explanation:
Electric potential at a point due to a particular charge (q) at r distance from that point is given as
V = kQ/r
where k = Coulomb's constant
For point P₁, the electric potential due to charge q, r distance away is given as
V₁ = kq/r
For point P₂, the electric potential due to charge q, (2r) distance away is given as
V₂ = kq/(2r)
This shows that the electric potential due to charge q at P1 is twice that experienced at P2 because of the same charge.
The electric potential at a point due to a particular only depends on the charge in question and the distance of that charge from that point.
If the charge and other parameters are constant, the electric potential at some distance away is inversely proportional to that distance. So, smaller r, indicates bigger electric potential.
<span>Days and nights are equal in length everywhere.(gradpoint)</span>
Answer:
A. Closed Series Circuit
Explanation:
Let's dissect the image. Just a heads up, I'm going to use a few of street/road analogies here. Think of the current as cars/people, the circuit path as streets/roads, and the resistors(in the bulbs) are like speed bumps.
- We have arrows dictating the direction of the current caused by the battery. If the circuit were open, it'd be as though we had a gap in a road so that no cars/people could go through. But <u>because we have a current, that indicates that the circuit is closed</u>.
- Next there's the question of the whether the resistors are in series or parallel. In simple cases like this, ask yourself if the resistors are on the same "street" or not. By that I mean, can you follow one line of current without breaking off to a different path? Here, it looks like the two resistors/bulbs are in series because they are on the same path.
So what you're looking at is a closed series circuit.
Explanation:
I'm not sure, but I would go for the more than A since its orbital speed is at its fastest and the sweep occurs in about the same period of days.