Question

A simple pendulum consists of a 4.9 kg point mass hanging at the end of a 3.1 m long light string that is connected to a pivot point. Calculate the magnitude of the torque (due to the force of gravity) around this pivot point when the string makes a 3.1 ◦ angle with the vertical. The acceleration of gravity is 9.81 m/s 2 . Answer in units of N · m.

Answer 1

Answer:

8.1 N-m

Explanation:

We are given that

Mass=m=4.9 kg

Length=L=3.1 m

$\theta=3.1^{\circ}$

$g=9.8m/s^2$

We have to find the magnitude of torque (due to the force of gravity).

We know that

$\tau=mgLsin\theta$

Using the formula

$\tau=4.9\times 9.8\times 3.1sin3.1^{\circ}$

$\tau=8.1 N-m$

Hence, the magnitude of  torque =8.1 N-m