Thermal energy transformation is taking place.
Answer: Law of conservation of energy
Heat Loss by the metal = Heat Gain by the water (Assume no heat loss to the environment)
M₁C₁ΔT₁= M₂C₂ΔT₂
Where
C₁ and C₂ = the specific heat capacities of the metal and water = C₁?, 4.182J/gK
ΔT₁ and ΔT₂ = Temperature changes of the metal and the water
ΔT₁ = (373 - 300.8)K and ΔT₂= (300.8 - 296.7)K convert to S.I units
M₁ and M₂ are the masses of the metal and water = 59.047g, but
M₂ = density x volume = 1kg/m³ x 0.1m³=0.1kg
Note: Volume of water = 100ml=0.1m³, also density of water = 1kg/m³
We have,
0.059kg x C₁J/KgK (373 - 300.8)K = 0.1kg x 4182J/kgK (300.8 - 296.7)K
4.259C₁=1715J/KgK
C₁=402.5J/KgK
The specific heat of the metal is 402.5J/KgK
Complete Question:
Two small objects each with a net charge of Q (where Q is a positive number) exert a force of magnitude "F" on each other. We
replace one of the objects with another whose net charge is 4Q. The original magnitude of the force on the Q charge was "F"; what is the magnitude of the force on the Q charge now?
Answer:
4 F₀
Explanation:
Assuming that we can treat to both objects as point charges, we can find the force "F" that one charge exerts upon the other applying Coulomb´s law, as follows:
F₀ = K*Q₀² / r₁₂²
If we replace one of the charges by one with a 4Q₀ charge, the new value of F will be as follows:
F₁ = K*Q₀*4Q₀ / r₁₂² =( K*Q₀² / r₁₂²)* 4 = 4* F₀
This value is reasonable, as the electrostatic force is a linear - type one, so it is possible to use the superposition principle (we can get the force exerted by one charge on another without considering the ones due to another charges)
Answer;
velocity(v) = 97.2 m/s ,
distance (S) = 100 m
determine time(t) = ?
We know that,
distance (S) = velocity(v) × time(t)
So, time (t) = distance ÷ velocity
= 100 ÷ 97.2
<em> t = 1.02 sec.</em>
<em>I hope this will help you.</em>
