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3 years ago

What would a drummer do to make the sound of a drum give a note of lower pitch?

Physics

2 answers:

wel3 years ago

6 0

Hitting it in the middle will make a lower pitch. Hitting in the corner will make a higher pitch.

stiks02 [169]3 years ago

5 0

A drummer would loosen the drum skin in order to make the sound of a drum give a note of lower pitch.
However, I am not entirely sure.

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A 55 newton force applied on an object moves the object 10 meters in the same direction as the force. What is the value of work

kifflom [539]

Answer: Option D: 5.5×10²Joules

Explanation:

Work done is the product of applied force and displacement of the object in the direction of force.

W = F.s = F s cosθ

It is given that the force applied is, F = 55 N

The displacement in the direction of force, s = 10 m

The angle between force and displacement, θ = 0°

Thus, work done on the object:

W = 55 N × 10 m × cos 0° = 550 J = 5.5 × 10² J

Hence, the correct option is D.

3 0

3 years ago

A force of 8.0 N is along x direction, another force of 6.0 N is along +y direction. If both forces are acting on a point object

Darya [45]

Answer:

Resultant force, R = 10 N

Explanation:

It is given that,

Force acting along +x direction, $F_x=8\ N$

Force acting along +y direction, $F_y=6\ N$

Both the forces are acting on a point object located at the origin. Let the resultant force of the object is given by R. So,

$R=\sqrt{F_x^2+F_y^2+F_xF_y\ cos\theta}$

Here $\theta=90^{\circ}$

$R=\sqrt{F_x^2+F_y^2}$

$R=\sqrt{8^2+6^2}$

R = 10 N

So, the resultant force on the object is 10 N. Hence, this is the required solution.

6 0

3 years ago

Is it true or false Objects with different masses can’t have the same momentum.

xenn [34]

Answer:

true

Explanation:

3 0

2 years ago

Read 2 more answers

What is the torque τb about axis b due to the force f⃗ ? (b is the point at cartesian coordinates (0,b), located a distance b fr

yKpoI14uk [10]

Check the attached file for the solution.

8 0

3 years ago

A 108 kg clock initially at rest on a horizontal floor requires a 653 N horizontal force to set it in motion. After the clock is

kifflom [539]

Answer:

$\mu_s=0.61$

$\mu_k=0.49$

Explanation:

Given that,

Mass of the clock, m = 108 kg

When the clock is not moving, force acting on it, $F_1=653\ N$

For the clock in motion, force acting on it, $F_2=527\ N$

To find,

$\mu_s\ and\ \mu_k$

Solution,

When an object is at rest, the force acting on it is called force due to static friction and if the object is in motion, the force acting on its called force due to kinetic friction.

Let $\mu_s$ is the coefficient of static friction. Force is given by :

$F_s=\mu_smg$

$\mu_s=\dfrac{F_s}{mg}$

$\mu_s=\dfrac{653}{108\times 9.8}$

$\mu_s=0.61$

Let $\mu_k$ is the coefficient of kinetic friction. Force is given by :

$F_k=\mu_kmg$

$\mu_k=\dfrac{F_k}{mg}$

$\mu_k=\dfrac{527}{108\times 9.8}$

$\mu_k=0.49$

8 0

3 years ago