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Lubov Fominskaja [6]
4 years ago
11

Plz help me answer this its 1 question will give brainliest

Physics
2 answers:
kolbaska11 [484]4 years ago
6 0
Circularity system........…….......
PIT_PIT [208]4 years ago
4 0

nerve cells; circulatory system; 5 hours

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A fish is able to jump vertically out of the water with a speed of 4.45 m/s. What is the speed of the fish as it passes a point
rjkz [21]

Answer:

Explanation:

given

initial velocity u = 4.45m/s

Height = 0.6m

g = 9.8m/s²

Required

final velocity v

Using the equation of motion;

v² = u²-2gH (upward motion of the fish makes g to be negative)

v² = 4.45²-2(9.8)(0.6)

v² = 19.8025-11.76

v² = 8.0425

v = 2.84 m/s

Hence the speed of the fish as it passes a point 0.6 m above the water is 2.84m/s

To get the time, we will use the formula

v = u - gt

2.84 = 4.45 - 9.8t

2.84-4.45 = -9.8t

-1.61 = -9.8t

t = 1.61/9.8

t = 0.164secs

Hence the time taken is 0.164secs

8 0
3 years ago
What probably causes continental lithosphere to become thinner and weaken?
Gemiola [76]
The cause of  continental lithosphere to becoming thinner and weaken is the Rifting and Continental Breakup. I hope my answer has come to your help. God bless and have a nice day ahead! Feel free to ask more questions here in Brainly.
7 0
3 years ago
Under normal conditions, what color do we expect diamonds to be?​
Ann [662]
Under normal lighting conditions, most diamonds appear to be colorless the naked eye. Many consumers think that all diamonds are colorless, however, in reality, they come in a wide range of colors. Actualcolor differences are very subtle.
8 0
3 years ago
uppose that the terminal speed of a particular sky diver is 150 km/h in the spread-eagle position and 320 km/h in the nosedive p
AysviL [449]

Answer:

4.55

Explanation:

The terminal speed of a diver is given by:

v_t=\sqrt{\frac{2mg}{C\rho A} } \\\\Where\ m=mass\ of \ driver,d=acceleration\ due\ to\ gravity,C=drag\ \\coefficient,A=cross\ sectional\ Area.\\\\Therefore:\\\\A=\frac{2mg}{C \rho v_t^2} \\\\For\ area\ with\ terminal\ speed\ in\ spread\ angle\ position(v_s):\\\\A_s=\frac{2mg}{C \rho v_s^2} \\\\For\ area\ with\ terminal\ speed\ in\ nose\ dive\ position(v_n):\\\\A_n=\frac{2mg}{C \rho v_n^2}\\\\Therefore\ since\ g,m,C,\rho\ are\ constant:\\\\

\frac{A_s}{A_n}= \frac{\frac{2mg}{C \rho v_s^2}}{\frac{2mg}{C \rho v_n^2}}\\\\\frac{A_s}{A_n}= \frac{v_n}{v_s} \\\\v_n=320\ km/h,v_s=150\ km/h\\\\\frac{A_s}{A_n}=\frac{320^2}{150^2} =4.55

4 0
3 years ago
At what point is the KINETIC ENERGY at its highest?
igomit [66]

Answer:

An object has the MOST kinetic energy when it's movement is the GREATEST.

Explanation:

8 0
3 years ago
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