Answer:
(a). The initial pressure is
(b). The final pressure is 
Explanation:
Given that,
Number of moles = 7
Temperature = 475 K
Initial volume = 0.50 m³
Expanded volume = 1.50 m³
We need to calculate the initial pressure
Using formula of pressure

Put the value into the formula


We need to calculate the final pressure
Using formula of pressure

After expansion,


Put the value into the formula
For thermal process,




Hence, (a). The initial pressure is
(b). The final pressure is 
The answer you are looking for is 400 joules.
To solve this problem it is necessary to apply the concepts related to linear momentum, velocity and relative distance.
By definition we know that the relative velocity of an object with reference to the Light, is defined by

Where,
V = Speed from relative point
c = Speed of light
On the other hand we have that the linear momentum is defined as
P = mv
Replacing the relative velocity equation here we have to







Therefore the height with respect the observer is



Therefore the height which the observerd measure for her is 0.56m
Answer:
quantitative
Explanation: quantitative research is better for scientist.
Answer:
i =
, i = 0.92 A
Explanation:
This exercise asks for the electromotive force, which can be calculated with Faraday's law
fem =
where the magnetic flux
Ф = B. A
bold letters indicate vectors. We can write this equation
Ф = B A cos θ
In this case the magnetic field is perpendicular to the page and the normal to the loop of the loop is also parallel to the page, therefore the angle is zero and the cosine is 1
the loop is
A = π r²
we substitute in the first equation
fem = - π r²
we substitute the values
fem = -π r² 1
fem = - π r²
to calculate the current let's use ohm's law
V = i R
R = ρ L / A'
where A 'is the area of the wire and L is the length of the loop
L = 2π r
V = i (ρ 2π r / A ')
I =
In this case
V = fem
I = fem / R
i =
In order to complete the calculation, you need the radius of the loop and / or the wire cutter.
if we assume that the loop has a radius of r = 1 cm = 0.01 m and an area of the wire A'= π 10⁻⁶ m² a radius of the wire 1 mm
i = - 10⁻² π 10⁻⁶ / ( 2 1.7 10-8)
i = 0.92 A