Answer:
atom has become cation
atom has lost 2 electrons
Explanation:
when atom loses electron they become positively charged and cation are positive ion
Answer:
The sphere is that the circular objects in the two-dimensional space (1) circle
(2) disk. Two-dimensional space is a set of points and the distance of that point, The two points of Sphere that length and center.
The sphere can be constructed as the name of surface form circle about any diameter. The circle is the special type of the revolution replacing the circle,
the sphere is the distance r is the radius of the ball and the circle is the center of the mathematical ball, as the center and the radius of the sphere is to respectively.
The ball and sphere have not to be maintained mathematical references as solid references. A sphere of any radius is centered at the number of zero.
Explanation: Hope this helps and good luck :)
Answer:
9.88 milivolt
Explanation:
Given: diameter d = 5.2 cm
magnetic field B_1 = 1.35 T, final magnetic field B_2 =0 T
t = 0.29 sec.
we know emf = - dΦ/dt
and flux Φ = BA
A= area
therefore emf ε = -A(B_2-B_1)/Δt

Answer:
compared to the incident angle, the refracted angle is 45.56⁰
Explanation:
From Snell's law;
n₁sin(I) = n₂sin(r)
Where;
n₁ is the refractive index of light in medium 1 = 1.2
n₂ is the refractive index of light in medium 2 = 1.4
I is the incident angle
r is the refractive angle

I = 56.439⁰
Applying snell's law

Therefore, compared to the incident angle, the refracted angle is 45.56⁰
Answer:

So then the answer for this case would be 29906 cal but we need to convert this into KJ and we know that 1 cal = 4.184 J and if we convert we got:

Explanation:
For this case we know the mass of the water given :

And we know that the initial temperature for this water is
.
We want to cool this water to the human body temperature 
Since the temperatures given are not near to 0C (fusion point) or 100C (the boling point) we don't need to use latent heat, then the only heat involved for this case is the sensible heat given by:

Where
represent the specific heat for the water and this value from tables we know that
for the water.
So then we have everything in order to replace into the formula of sensible heat and we got:

So then the answer for this case would be 29906 cal but we need to convert this into KJ and we know that 1 cal = 4.184 J and if we convert we got:
