Answer:
What is velocity?
v = d/t = distance / time you need to know this formula !
= 10 m/ 4 s = 2.5 m/s
Explanation:
Answer:
= 0.0050 M
= 0.0155 M
Explanation:
Initial moles of
= 0.072 mole
Volume of container = 3.9 L
Initial concentration of
The given balanced equilibrium reaction is,

Initial conc. 0.018 M 0
At eqm. conc. (0.018-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[I]^2}{[I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BI%5D%5E2%7D%7B%5BI_2%5D%7D)

we are given : 
Now put all the given values in this expression, we get :


So, the concentrations for the components at equilibrium are:
![[I]=2\times x=2\times 0.0025=0.0050](https://tex.z-dn.net/?f=%5BI%5D%3D2%5Ctimes%20x%3D2%5Ctimes%200.0025%3D0.0050)
![[I_2]=0.018-x=0.018-0.0025=0.0155](https://tex.z-dn.net/?f=%5BI_2%5D%3D0.018-x%3D0.018-0.0025%3D0.0155)
Hence, concentrations of
and
are 0.0050 M ad 0.0155 M respectively.
Answer:
Light provides brightness to see and also light carries energy
Answer:
A) 1.88 * 10^17 m
B) 1.22 * 10^34 J
C) 1.95 * 10^34 J
Explanation:
Parameters given:
Mass of planet = 7.00 * 10^25 kg
Radius of orbit = 6.00 * 10^11 m
Force exerted on planet = 6.51 * 10^22 N
Velocity of planet = 2.36 * 10^4 m/s
A) The distance traveled by the planet is half of the circumference of the orbit (which is circular).
The circumference of the orbit is
C = 2 * pi * R
R = radius of orbit
C = 2 * 3.142 * 6.0 * 10¹¹
C = 3.77 * 10¹² m
Hence, distance traveled will be:
D = 0.5 * 3.77 * 10¹²
D = 1.88 * 10 ¹² m/s
B) Work done is given as:
W = F * D
W = 652 * 10²² * 1.88 * 10¹¹
W = 1.22 * 10³⁴ J
C) Change in Kinetic energy is given as:
K. E. = 0.5 * m * v²
K. E. = 0.5 * 7 * 10^25 * (2.36 * 10^4)²
K. E. = 1.95 * 10³⁴ J
As per Newton's II law we know that

here we know that

so here we will have

so here if we need to increase the acceleration we need to increase the applied force while on increasing the mass or on increasing the friction force the acceleration will decrease.
So here correct answer will be
<em>A) force on the object.</em>