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kari74 [83]
3 years ago
14

Suppose there is a large amount of (weakly interacting) dark matter between us and a distant galaxy. How will this affect our vi

ew of the distant galaxy?
Physics
1 answer:
leonid [27]3 years ago
7 0

Answer:

Dark matter does not affect our view, humans can see through them.

Explanation:

They do not affect our view because we can see right through the (weakly interacting) dark matter, as they do not interact or interfere with electromagnetic force.

Dark matter are often invisible substances and are difficult to spot because they don't absorb or reflect light.

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a car traveling at a velocity of 2 m/s undergoes an acceleration of 4.5 m/s^2 over a distance of 340 m. How fast will it be goin
ra1l [238]
Vi = 2m/s
a= 4.5 m/s 
d= 340 m
vf= ?

use this equation ...  vf^2=vi<span>^2+2ad

you should get vf = 55.3
hope this helps </span>
3 0
3 years ago
The Doppler effect using ultrasonic waves of frequency 2.25 × 106 Hz is used to monitor the heartbeat of a fetus. A (maximum) be
miss Akunina [59]

Answer:

v = 2.88 \times 10^7 m/s

Explanation:

As per Doppler's effect we know that the frequency of the sound that is observed by the detector is the reflected sound

This reflected sound is given as

f' = f (\frac{v - v_h}{v + v_h})

f' = 2.25\times 10^6(\frac{v - 1540}{v + 1540})

so we know that the beat frequency is

\Delta f = 240 Hz

so we will have

f - f' = \Delta f

2.25 \times 10^6 - 2.25\times 10^6(\frac{v - 1540}{v + 1540}) = 240

1 - (\frac{v - 1540}{v + 1540}) = 1.07 \times 10^{-4}

so we have

0.99989 = (\frac{v - 1540}{v + 1540})

1.99989\times 1540 = 1.067 \times 10^{-4} v

v = 2.88 \times 10^7 m/s

4 0
4 years ago
A 14.3-g bullet is fired into a 5.21 kg block of wood. The block is attached to a spring that has a spring force constant of 450
Natasha2012 [34]

Answer:

The initial speed of the bullet is v_{o} = 889.199\,\frac{m}{s}.

Explanation:

The collision between bullet and block is inelastic and let suppose that motion occurs on a horizontal surface, so that changes in gravitational potential energy can be neglected. Initially, the intial speed of the bullet-block system can be determined with the help of the Work-Energy Theorem and the Principle of Energy Conservation:

K = U_{k} + W_{loss}

\frac{1}{2}\cdot (5.224\,kg)\cdot v^{2} = \frac{1}{2}\cdot \left(450\,\frac{N}{m}\right)\cdot (0.22\,m)^{2} + (0.35)\cdot (5.224\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right) \cdot (0.22\,m)

The initial speed of the bullet-block system is:

v \approx 2.383\,\frac{m}{s}

Now, the initial speed of the bullet is determined by applying the Principle of Momentum Conservation:

(0.014\,kg)\cdot v_{o} = (5.224\,kg)\cdot \left(2.383\,\frac{m}{s} \right)

v_{o} = 889.199\,\frac{m}{s}

6 0
3 years ago
A car travels 90 km per hour how many how many Kilometres of distance does it travel in one second ​
gavmur [86]

Answer:

Its Moving at a constant Speed of 90km/hr

You can convert this speed to Meters/Second or Change it to Km/Second(Because we need our distance in Km)

So 90km/hr x 1/60 x1/60

=90km/3600sec

v=0.025km/sec

When an Object Moves at Constant Speed... Its displacement(distance) is given by

d=vt

given v=0.025km/sec

t=1sec

d=0.025km/sec x 1sec

d=0.025km.

7 0
3 years ago
Read 2 more answers
A wheelbarrow is an example of what type of lever
grin007 [14]

A wheelbarrow is a 2nd class lever. Your hands on the handles give the effort. The load inside the wheelbarrow is the resistance. The wheel is the fulcrum. When you lift up the handles, the load goes up in the same direction.

3 0
3 years ago
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