Answer:
heterozygous (Aa) are 0.085 = or 8.54%
Step-by-step explanation:
The heterozygous individuals are carriers of the sickle cell trait. They have a genotype of Aa and are represented by the 2pq term
in the H-W equilibrium equations.
According to the question 0.2% of the population is affected with sickle cell anemia, thus q^2
= 0.2% = 0.002 in decimal. So, q =
sqr(q^2)
or sqr(0.002) =
0.04472
and p + q = 1, thus p = 1 – q = 1 – 0.04472 = 0.96
Thus, A allele has a frequency of 0.96 and the a allele has a frequency of 0.04472. Therefore, the
percentage of the population that is heterozygous (Aa) and are carriers is = 2pq = 2× 0.04472× 0.96 =0.085 = or 8.54%
Answer:
3.06417777
Step-by-step explanation:
cos(40)=x/4
$1.58 per bottle
$1.74 per bottle
the first package costs the least per bottle!
Answer:
[1, 0], [-1, 0], [-2, 0]
Step-by-step explanation:
[x + 1][x + 2][x - 1] >> Factored Form
When set equal to zero, you get the above roots.
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