The answer is C. The 4th period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd period class.
<span>(1 + 5 ) x 2 = 12 1
+ [(5 x 2) – 2] = 10 </span>
<span>1 + [5 x (2 – 2)] = 1 [1
+ (5 x 2)] – 2 = 9</span>
<span>8 = 12 – [8 / (4 / 2)] 11 = 12 – [(8 / 4) / 2]</span>
<span>½ = [(12 – 8 ) / 4] / 2 20
= 6 x 4 – 4 x 5 </span>ß----can’t figure it out …sorry
<span>0 = 6 x
(4 – 4) x 5 100
= [(6 x 4) – 4] x 5</span>
<span>24 = [14 –(8 -2)] x 3 0=
(14 –8) – (2 x 3)</span>
<span>12 = [{14 – 8)
- 2] x 3 12
= 14 – [8 - (2 x 3)]</span>
Answer:
point A lol
Step-by-step explanation:
It goes up by 8 points, and 6 points right
Answer:
h=4in
length=5inch
width=8inch
volume=160inch3
Step-by-step explanation:
using the formula: v=whl
h=V
lw=160
5·8=4in
With overlapping, yes. He would need a right triangle and two equilateral triangles. Hope this helps!
