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3 years ago

Simplify the following expression:

1 answer:

4 0

If you would like to simplify 7x − 4y + 5z − 2x − 10y + z, you can do this using the following steps:

7x − 4y + 5z − 2x − 10y + z = 7x - 2x - 4y - 10y + 5z + z = 5x - 14y + 6z

The correct result would be 5x - 14y + 6z.

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Before ordering food for a company barbecue the president took a poll. She asked people if they would eat the ribs, hamburgers,

Vinvika [58]

Answer:

The complete question is as shown in the attached figure 1

The Venn diagram is the attached figure 2

Let: R⇒ribs , H⇒hamburgers and C⇒corn

People would eat all three = 53

People would eat only R and H = 56 - 53 = 3

People would eat only C and H = 54 - 53 = 1

People would eat only R and C = 55 - 53 = 2

People would eat only H = 60 - (53+3+1) = 60 - 57 = 3

People would eat only R = 59 - (53+3+2) = 59 - 58 = 1

People would eat only C = 56 - (53+1+2) = 0

See Vinn diagram.

=========================================================

a. How many people did not want any of these foods?

people did not want any of these foods = 64 - (53+3+1+2+3+1) = 1

b. How many people would eat ribs but not corn?

people would eat ribs but not corn = 1+3 = 4

c. How many people would eat something as long as it was not a hamburger?

people would eat something as long as it was not a hamburger= 1+2 = 3

d. How many people would eat only corn?

people would eat only corn = 0

e. How many people would eat exactly two foods?

people would eat exactly two foods = 1 + 2 + 1

6 0

3 years ago

Inez’s piggy bank has 10 quarters, 6 dimes, 3 nickels, and 2 pennies. What is the probability of Inez picking a nickel out of th

Luba_88 [7]

The answer is 1/7 :)

4 0

2 years ago

Read 2 more answers

Peter attends 6 dance lessons each week all year long a year has 52 weeks peter missed 5 dance lessons while sick how many dance

viktelen [127]

6 lessons per week multiplied by the number of weeks in a year
6 x 52 = 312
total - 5 missed
312 - 5 = 307 dance lessons

5 0

3 years ago

Can someone help me please

Darya [45]

Answer:

a^7/b^6

Step-by-step explanation:

3 0

3 years ago

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago