Question

A student is ordering a flower arrangement. She can choose any combination of roses and carnations for flower arrangement, and she does not want to spend more than $30. If roses cost three dollars each and carnations cost two dollars each which inequality represents all possible combinations of X roses and y carnations?
3X + 2y<30
2x+3y<_ 30
2X+ 3Y > 30
3X + 2Y<_ 30

Answer 1

Answer:

The inequality is;

2x + 3y ≤ 30

Step-by-step explanation:

Here, we want to select which of the inequalities represent all possible combinations of x roses and y carnations.

From the question, we are told that roses cost $3 and carnations cost $2

So, by buying x roses, total amount spent = $3x

By buying y carnations, total amount spent = $2y

Now, we are told that she does not want to spend more than $30, this means she can spend less than $30 or exactly $30 but cannot spend more than $30

So, by mathematical convention, we say the sum of the roses and carnations bought is less than or equal to $30

Thus we have;

2x + 3y ≤ 30