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just olya [345]
3 years ago
13

If a child pulls a sled through the snow on a level path with a force of 60 N exerted at an angle of 39° above the horizontal, f

ind the horizontal and vertical components of the force.
Physics
1 answer:
White raven [17]3 years ago
5 0

Explanation:

Given that,

Force with which a child pulls a sled, F = 60 N

It is at an angle of  39° above the horizontal. We need to find the horizontal and vertical components of the force.

The horizontal component is given by :

F_x=30\ cos(39)=23.31\ N

The vertical component is given by :

F_y=30\ sin(39)=18.87\ N        

So, the horizontal and vertical components of the force are 23.31 N and 18.87 N. Hence, this is the required solution.

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The speed limit on an interstate highway is posted at 75mi/h. What is the speed in kilometers per hour? In feet per second?
Tatiana [17]

Answer:

See explanation

Explanation:

The conversion factor from miles per hour to kilometers per hour is 1.609344.

Hence;

To convert 75mi/h to kilometers per hour,

75mi/h * 1.609344 = 120.7 kilometers per hour

b)

To convert 75mi/h to feet per second

Since

1 mile per hour = 1.46667 foot per second

75mi/h = 75 * 1.46667 = 110 feet  per second

5 0
3 years ago
What does doubling the number of coils do to the strength of the electromagnet?
Radda [10]
You double the strength of the electromagnet. The number of coils and the strength of the electromagnet are proportional.
5 0
4 years ago
A proton moves with a speed of 1.17 105 m/s through Earth's magnetic field, which has a value of 50.0 µT at a particular locatio
vlabodo [156]

a) Southward you need to apply right hand rule. If you close your hand to the east, your thumb will indicate south.

b) Given the equation for Magnetic Force

F= qVB

Replacing

F= (1.16*10^{-19})(1.17*10^5)(50*10^{-6})

F=9.36*10^{-19}

c) Given the second Newton's Law by

F_g = 1.67*10^{-27}*9.81

F_g = 1.64*10^{-26}

Given the electric force by,

F_e = 1.6*10^{-19}*1.5*10^2

F_e = 2.4*10^{-17}N

F=9.36*10^{-19}N

7 0
3 years ago
If a pitch vibrates at 880 cycles, the octave below would vibrate at ____ cycles. 220 440 660 1760
eduard

Answer:

If a pitch vibrates at 880 cycles, the octave below would vibrate at 440 cycles.

Explanation:

Pitch of sound is defined as relative highest and the lowest point of sound. The pitch is dependent on frequency of vibration.

Octave is defined as a tone which is formed due to merging of two different tone. The resultant tone is merged so well that it sound like a single tone.

Thus, Number cycle in octave = \frac{number of cycles in a pitch}{2}

Number cycle in octave = \frac{880}{2}

Number cycle in octave = 440

Thus, If a pitch vibrates at 880 cycles, the octave below would vibrate at 440 cycles.

7 0
3 years ago
An object is traveling such that it has a momentum of magnitude 23.3 kg.m/s and a kinetic energy of 262 J. Determine the followi
Crazy boy [7]

Explanation:

It is given that,

Momentum of an object, p = 23.3 kg-m/s

Kinetic energy, E = 262 J

(a) Momentum is given by, p = mv

23.3 = mv...........(1)

Kinetic energy is given by, E=\dfrac{1}{2}mv^2

m = mass of the object

v = speed of the object

E=\dfrac{1}{2}\times (mv)\times v

262=\dfrac{1}{2}\times 23.3\times v

v = 22.48 m/s

(2) Momentum, p = mv

m=\dfrac{p}{v}

m=\dfrac{23.3\ kg-m/s}{22.48\ m/s}

m = 1.03 Kg

Hence, this is the required solution.

8 0
4 years ago
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