The rate of change of a linear equation (first degree) is equivalent to the slope of a line. Slope is described as the vertical movement (rise) of the line over its horizontal counterpart (run). In determining the rate of change or slope (m) given 1 data point (x',y'), point-slope form is applicable. Point-slope form is: (y-y') = m (x-x'). Substitute the given point (-5,-1) in the equation. By substitution, [y-(-1)] = m [x-(-5)]. Re-arranging the equation, the rate of change or slope is, m = (y+1)/(x+5).
From the diagram given;
ABCD is a quadrilateral;
Line |EF| bisects the line |AD| and line |CD|,
Thus, from the given options;
LINE |EF| is a segment bisector is the only correct option.
Answer:
299 miles per hour
Step-by-step explanation:
![v=\frac{234}{\sqrt[3]{\frac{p}{w}}}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B234%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7Bp%7D%7Bw%7D%7D%7D)
![v=\frac{234}{\sqrt[3]{\frac{1311}{2744}}}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B234%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1311%7D%7B2744%7D%7D%7D)
Therefore, the velocity of the car at the end of a drag race is 299 miles per hour
Answer:
thank you for giving me points ;)
Step-by-step explanation:
Y=24x+48
24 per hour (x) plus the 48 she already made would equal a total (y).
