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mel-nik [20]
3 years ago
9

The metal is easily shaped and does not ....... with water

Chemistry
2 answers:
forsale [732]3 years ago
4 0
The metal is easily shaped and does not react with water
xz_007 [3.2K]3 years ago
3 0

the metal is easily shaped and does not contract with water

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A sample of nitrogen gas had a volume of 500. mL, a pressure in its closed container of 740 torr, and a temperature of 25 °C. Wh
Nat2105 [25]

Answer:

527.68 mL

Explanation:

We will assume that nitrogen is behaving as ideal gas here.

For ideal gas the gas law is:

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

Where

P1= initial pressure = 740 torr

V1= initial volume = 500mL

T1= initial temperature = 25⁰C = 298 K

P2= final pressure = 760 torr

V2= final volume = ?

T2= final temperature = 50⁰C = 323 K

Putting values in the gas law

Final volume = \frac{740X500X323}{298X760}= 527.68 mL

5 0
3 years ago
What is an isotope? Give an example (use the full name! Simply listing the element is not a correct answer!)
Alina [70]

Answer:

Isotopes are variations of chemical elements that have the same number of protons but different number of neutrons.

Explanation:

3 0
3 years ago
HELP - a solution NaOCl was prepared at pH 10.3. calculate the concentration of the salt formed. Given Ka for HOCl=3.0x10^-8
GenaCL600 [577]
First we dissociate the salt

NaOCl ⇒ Na⁺ + OCl⁻
note that [NaOCl] = [OCl⁻]

note that Na⁺ does not undergo hydrolysis so it is a spectator.
OCl⁻ can reform HOCl in an equilibrium, with OCl⁻ acting as the base.

OCl⁻ + H₂O ⇄ OH⁻ + HOCL

<span>Ka for HOCl = 3.0x10^-8, therefore

Kb for OCL</span>⁻ = Kw / (Ka for HOCl)
                       = 1.0 × 10⁻¹⁴ / 3.0 <span>× 10⁻⁸
                       = 3.3 × 10⁻⁷

</span>since Kb for OCl⁻ is given, and the pH is given, then [OCl⁻] must be found, and [OCl⁻] = [NaOCl]

convert the pH into [OH⁻]:
pOH = 14 - pH = 14 - 10.3 = 3.7
[OH⁻] = 10^(-3.7) = 1.995 × 10⁻⁴

set up equib table

          OCl⁻                + H₂O    ⇄      OH⁻        +           HOCl
  ST     x                                               0                             0
 +Δ    -1.995 × 10⁻⁴                   +1.995 × 10⁻⁴        +1.995 × 10⁻⁴
---------------------------------------------------------------------------------
 EQ:   x -1.995 × 10⁻⁴                 1.995 × 10⁻⁴          1.995 × 10⁻⁴

Kb = [OH⁻][HOCl] / [OCl⁻]
3.3 × 10⁻⁷ = (1.995 × 10⁻⁴)² / (x -1.995 × 10⁻⁴ )
x = 1.1963 × 10⁻¹ M = [OCl⁻] = [NaOCl]

The concentration of the salt formed, <span>NaOCl,</span> is 1.2 × 10⁻¹ M

7 0
3 years ago
slaked lime (Ca(OH)2) is formed from quicklime (CaO) by the addition of water. What mass of slaked lime can be produced from a m
omeli [17]
The Law of Conservation of Mass says that there can be no more or no less mass after a chemical reaction, so 24.4g+ 12.3 g has to equal the mass of Ca(OH)2
4 0
3 years ago
When does a cold front develop? A. when two masses of warm air meet B. when a cold air mass invades a warm air mass C. when two
uranmaximum [27]

B. when a cold air mass invades a warm air mass

6 0
3 years ago
Read 2 more answers
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