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3 years ago

-8(x-3y) when x=-2 and y=-4

2 answers:

8 0

-8(x-3y) when x=-2 and y=-4. To solve the answer, we need to do like this
-8(x-3y)
Substitute x with -2 and y with -4
-8[-2-3(-4)]
=-8(-2+12)
=-8(10)
=-80
Or
-8(x-3y)
Use distributive property
-8(x)-8(-3y)
=-8(x)+24(y)
Substitute x with -2 and y with -4
-8(-2)+24(-4)
=16-96
=-80. As a result, the correct answer is -80. Hope it help!

seropon [69]3 years ago

6 0

First let's put in the values.

-8(-2-3·-4)

Solve using PEMDAS

Parentheses (Multiplication)

-8(-2+12)

Parentheses (Addition)

-8 · 10

Multiplication

-80

The answer is -80

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Which equation could be used to find the length of the hypotenuse?

Komok [63]

Answer:

<h3>(base)² + (altitude)² = (hypotenuse) ²</h3>

Therefore,

2²+5² = c² will be matched.

7 0

2 years ago

| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the

Westkost [7]

Answer:

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

Left Speed(km/h) Time

Car: 12PM X

Van: 12PM 60

Car/Van

DistanceCar AB + z

DistanceVan Az

Ratio: (AB+z)/Az = 7/5

Time until both meet = T (in hours)

Distance Car: xT

Distance Van: 60T

====

xT = AB + z

60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is: time (hr) = 108 km/(84 km/h)

time = 1.286 hours

Distance for at 1.289 hours is: distance (km) = (60 km/h)*(1.286 h)

distance = 77.14 km

At 1.286 hours, the car reverses direction. The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours. The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let t be the time after 1.286 hours that both vehicles meet/collide.

t*(60 km/h) + t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

==============

CHECK

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

YES

3 0

2 years ago

Find the value of x in 4:x::x:16

AnnyKZ [126]

Given:

4:x::x:16

To find:

The value of x.

Solution:

We have,

4:x::x:16

It means, we have

4:x = x:16

It can be rewritten as

$\dfrac{4}{x}=\dfrac{x}{16}$

On cross multiplication, we get

$4\times 16=x\times x$

$64=x^2$

Taking square root on both sides.

$\pm \sqrt{64}=x$

$\pm 8=x$

Since ratio can be negative or positive, therefore, the value of x is either -8 or 8.

4 0

3 years ago

Find the measures of the four numbered angles

Genrish500 [490]

First, find out x
x+15+2x+15=180
3x+30=180
3x=150
x=50
so the two angels are x+15=65(let's name is ∠5 for convenience), and ∠6= 2x+15=115
notice the two inner lines are marked as congruent, so
∠4=∠5=65
∠1=180-∠4-∠5=180-65-65=50
Name the right bottom angle ∠7, ∠3=∠7 and ∠3+∠7=the exterior angle 100 degree, therefore, ∠3=50
∠2+∠3=∠4, therefore, ∠2=∠4-∠3=65-50=15
∠1=50, ∠2=15, ∠3=50, ∠4=65

5 0

3 years ago

HELP ASAP Find the 15th term or the geometric sequence 7, -21, 63,

mihalych1998 [28]

<h3>Answer:</h3>

33480783

<h2>Step-by-step explanation:</h2>

Finding the Common Ratio:

We know that the formula for the common ratio of a GP is:

r = aₙ / (aₙ₋₁) (Where n is any integer)

replacing the values, taking n=2

r = -21 / 7

r = -3

Solving for the 15th Term:

We know that the Formula for the nth term of a GP:

G(n) = a * r ⁿ⁻¹ (where a is the first term and r is the common ratio)

replacing the values (taking n = 15 since we need the 15th term)

G(15) = 7 * (-3)¹⁴

G(15) = 33480783

Hence, the 15th term of the given GP is 33480783

5 0

3 years ago