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Leona [35]
4 years ago
5

In Sir Isaac Newton's time in the early 1700s, what was the general consensus among scientists on the properties of light?

Chemistry
2 answers:
Alex777 [14]4 years ago
6 0

Answer:

 

Light is composed of particles and travels in a straight line.

Explanation:

PF The majority of scientists in the early 1700s agreed that light must be particle-like, since it was apparent that light traveled in a straight line and was able to pass through a vacuum. Their logic was that since sound travels in waves and can't travel though a vacuum, light must consist of something other than waves, such as particles.

Mekhanik [1.2K]4 years ago
3 0

Answer:

Light is composed of particles and travels in a straight line.

Explanation:

The general consensus among scientists in Sir Isaac Newton's time in the early 1700s was that light was composed of a steady stream of particles, since it was observed that light traveled in a straight line and was able to pass through a vacuum. They argued along the lines of Sir Isaac Newton that since sound travels in waves and cannot travel though a vacuum, light must consist of something other than waves, such as particles.

Also, on reflection of light from rough surfaces, the particle theory suggests that if the surface is very rough, the particles bounce away at different angles from the surface, scattering the light as is confirmed by experimental observation.

In his 1704 book Opticks, Sir Isaac Newton stated that "Light is never known to follow crooked passages nor to bend into the shadow". This idea lent support to the particle theory, which proposes that light particles must always travel in straight lines. If the particles encounter the edge of a barrier, then they will cast a shadow because the particles not blocked by the barrier continue on in a straight line and cannot spread out behind the edge. This was observed in eclipses as well as formation of shadow of objects.

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Read 2 more answers
25 g of 116oC steam are bubbled into 0.2384 kg of water at 8oC. Find the final temperature of the system.
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Answer: The final temperature of the system will be 13.14^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of steam = 25 g

m_2 = mass of water = 0.2384 kg = 238.4 g   (1kg=1000g)

T_{final} = final temperature = ?

T_1 = temperature of steam = 116^oC

T_2 = temperature of water = 8^oC

c_1 = specific heat of steam = 1.996J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

25g\times 1.996J/g^0C\times (T_{final}-116)=-[238.4g\times 4.184J/g^0C\times (T_{final}-8)]

T_{final}=13.14^0C

Therefore, the final temperature of the system will be 13.14^0C

7 0
3 years ago
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