3,7-dibromo-4,6-dichloro oct-5-ene-1,2-diol. --- show its structure by photo.
2 answers:
Explanations:- Looking at the given name, the parent chain name is Oct and Oct stands for eight carbons.
The suffix -ene at number 5 stands for a double bond between carbon number 5 and 6.
Bro stands for Br. Since the name has dibromo means there are two Br at number 3 and 7 carbons.
Similarly, there are two Cl at number 4 and 6 carbons.
Suffix -ol is used for OH group. The given name has 1,2-diol means there are two OH groups at number 1 and 2 carbons.
So, to draw the structure of the compound we put 8 carbons in a chain and then but a double bond between number 5 and 6 carbons. Put OH at number 1 and 2 carbons, put Br at number 3 and 7 carbons and Cl at number 4 and 6 carbons. If any of the carbons octet (four bonds) is still incomplete then we attach H atoms to it.
So, the structure of the compound is as given below:
You might be interested in
Alkene on Hydration yield Alcohols. When Asymmetric Alkenes are treated with water in the presence of acid they follow Markovnikoff rule, and the Hydrogen of incoming reagent goes to that carbon which contain more number of Hydrogen atoms. The reverse (Anti-Markovnikoff) is done by carrying out Hydroboration reaction.In this case the Hydrogen atom of incoming reagent goes to that carbon which contains less number of Hydrogen atoms. In this reaction both -H and -OH adds in syn fashion. The Hydroboration reaction of Chloestrol is shown below,
Answer:
191.6 g of CaCl₂.
Explanation:
What is given?
Mass of HCl = 125.9 g.
Molar mass of CaCl₂ = 110.8 g/mol.
Molar mass of HCl = 36.4 g/mol.
Step-by-step solution:
First, we have to state the chemical equation. Ca(OH)₂ react with HCl to produce CaCl₂:
Now, let's convert 125.9 g of HCl to moles using the given molar mass (remember that the molar mass of a compound can be found using the periodic table). The conversion will look like this:
Let's find how many moles of CaCl₂ are being produced by 3.459 moles of HCl. You can see in the chemical equation that 2 moles of HCl reacted with excess Ca(OH)₂ produces 1 mol of CaCl₂, so we state a rule of three and the calculation is:
The final step is to find the mass of CaCl₂ using the molar mass of CaCl₂. This conversion will look like this:
The answer would be that we're producing a mass of 191.6 g of CaCl₂.