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-BARSIC- [3]
3 years ago
9

What is always true of a binary compound ?

Chemistry
1 answer:
cestrela7 [59]3 years ago
6 0
The correct answer is C.
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Beaker 3 shows a clear chemical reaction.
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Hannah does an experiment she has two colorless chemicals that she mixes together in a beaker which of the following indicates t
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1.the chemical change color from colorless to purple

2. A yellow gas forms

3.a brown solid forms in the bottom of the beaker

4.the temperature of the chemicals rises 15 Celsius

Explanation:

All of the options are proofs that chemical change has occurred.

A chemical change is one with the following properties:

  • A new kind of matter is usually formed as seen by the gas evolution and the formation of the insoluble precipitate i.e brown solid at the bottom of the beaker.
  • They are not easily reversible.
  • Usually accompanied by energy changes as seen in the rise in temperature.
  • Color changes can also infer chemical changes in a reaction.

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8 0
3 years ago
References Use the References to access important values if needed for this question A student ran the following reaction in the
ANTONII [103]

Answer:

19.27

Explanation:

Some values are corrected from correct source.Thus,

Moles of SO₂ = 8.19x10⁻² moles

Moles of O₂ = 8.10x10⁻² moles

Volume = 1 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Concentration of SO₂ = 8.19x10² M

Concentration of O₂ = 8.10x10 M

Considering the ICE table for the equilibrium as:

                    2SO₂ (g) +    O₂ (g)     ⇔          2SO₃ (g)

t = o              8.19x10⁻²      8.19x10⁻²

t = eq                -2x                  -x                      2x

--------------------------------------------- --------------------------

neq:    8.19x10⁻² -2x       8.19x10⁻² -x                      2x

Given:  

Equilibrium concentration of  O₂ = 5.98x10⁻² M  = 8.19x10⁻² -x

Thus, x = 0.0212 M

[SO₂] = 8.19x10⁻² - 2*0.0212 = 0.0395 M

[SO₃] = 2*0.0212 = 0.0424 M

The expression for the equilibrium constant is:

K_c=\frac {[SO_3]^2}{[SO_2]^2[O_2]}  

K_c=\frac{{0.0424}^2}{{0.0395}^2\times 0.0598}  

K = 19.27

4 0
3 years ago
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