All categories

3 years ago

Which statements describe how chemical formulas, such as H2O, represent compounds? Check all that apply.

Physics

2 answers:

Pani-rosa [81]3 years ago

5 0

The statements that apply in this case are:

They show the elements that make up a compound.

They show the types of atoms that make up a molecule.

They show the number of each type of atom in a molecule.

posledela3 years ago

3 0

Answer:its the second one

Explanation:

You might be interested in

Keisha is making a diagram of a simple machine in the body.

Amiraneli [1.4K]

Answer:

Sorry for being late. It is...

A.) X: Load, Y: Fulcrum, Z: Lever

3 0

3 years ago

Read 2 more answers

A ray of light strikes a plane mirror at an angle of incidence 35°. If the mirror is rotated through 10°.

xxTIMURxx [149]

Answer:

1 35°

2 20°

3 50°

..............

7 0

3 years ago

The diagram below shows a wave with its wavelength indicated in red.

lisabon 2012 [21]

C. It will decrease

5 0

4 years ago

Read 2 more answers

Which statement correctly describes the reactivity of noble gases, according to the octet rule? Their atoms have eight electrons

Kipish [7]

Answer:

The correct option is : Their atoms have eight electrons in their valence shells, so noble gases are very unreactive.

Explanation:

The octet rule state that atoms tend to complete their last energy levels with eight electrons, and that this configuration make them very stable and unreactive.

Noble gases are characterized as unreactive atoms, and this is associated with the fact that they have a complete valence shell, it means that they have eight electrons on it (they follow the octet rule).

Atoms with less electrons on their valence shells tend to react with another atom, forming bonds, to complete their valence shells (with eight electrons).

5 0

3 years ago

a man drags a 8.10 kg bag of mulch at a constant speed, applying a 29.5 N at 38°. what is the coefficient of friction?

lesantik [10]

Answer:

The coefficient of friction is 0.38.

Explanation:

The free body diagram is drawn below.

Let $f$ be frictional force acting in the backward direction as shown. Let the coefficient of friction be $\mu$ . Let $N$ be the normal reaction force acting on the bag.

Given:

Mass of the bag is, $m=8.10\textrm{ kg}$

Force acting at $\theta = 38$ ° is $F= 29.5\textrm{ N}$

Acceleration due to gravity is, $g=9.8\textrm{ }m/s^{2}$

The force F can be resolved into its components as $F_{x}=F \cos \theta$ and $F_{y}=F \sin \theta$

Therefore,

$F_{x}=29.5\cos(38)=23.25\textrm{ N}\\F_{y}=29.5\sin(38)=18.16\textrm{ N}$

Now, as there is no acceleration in vertical direction, therefore,

Sum of upward forces = Sum of downward forces

$N+F_{y}=mg\\N=mg-F_{y}=8.10\times 9.8-18.16\\N=79.38-18.16=61.22\textrm{ N}$

Now, as the bag is moving at a constant speed, so acceleration in the horizontal direction is also zero as acceleration is the rate of change of velocity.

Therefore, backward force = forward force.

$f=F_{x}\\f=23.25\textrm{ N}$

Now, frictional force is given as:

$f=\mu N\\\mu = \frac{f}{N}=\frac{23.25}{61.22}=0.38$

Therefore, the coefficient of friction is 0.38.

8 0

3 years ago