Complete question:
An air-filled parallel-plate capacitor has plates of area 2.90 cm2 separated by 2.50 mm. The capacitor is connected to a(n) 18.0 V battery. Find the value of its capacitance.
Answer:
The value of its capacitance is 1.027 x 10⁻¹² F
Explanation:
Given;
area of the plate, A = 2.9 cm² = 2.9 x 10⁻⁴ m²
separation distance of the plates, d = 2.5 mm = 2.5 x 10⁻³ m
voltage of the battery, V = 18 V
The value of its capacitance is calculated as;
Therefore, the value of its capacitance is 1.027 x 10⁻¹² F
Answer:
Explanation:
To analyze the behavior of black bears during the night. To describe how black bears adapt to life near human. To evaluate the decline in the number of black bear.
<span> </span>For any prism-shaped geometry, the volume
(V) is assumed by the product of cross-sectional area (A) and height (h).
<span> V = Ah </span>
<span>
Distinguishing with respect to time gives the
relationship between the rates.
dV/dt = A*dh/dt</span>
<span> in the meantime the area is not altering </span>
<span>
dV/dt = π*(1 ft)^2*(-0.5 ft/min) </span>
<span>
dV/dt = -π/2 ft^3/min ≈ -1.571 ft^3/min
Water is draining from the tank at the rate of π/2
ft^3/min.</span>
Thank you for posting your question here at brainly. I hope the answer will help you. Below is the solution. Feel free to ask more question.
<span>torque = rF
= 0.1(10)
=1 Nm</span>
Direct variation involves ration and proportions, so
you need to set up the proportion:
<span>11 / 75 = x / 65
Cross multiplying:
75x = 11*65
x = (11*65)/75
Solving, we get x = 9.533, </span>
<span>which rounds off to 9.5
Therefore, the spring will stretch up to 9.5 inches with 65 attached.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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