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3 years ago

How many licks dose it take to eat a lolipop

Physics

2 answers:

artcher [175]3 years ago

8 0

Answer: that's funny i think it takes 1000000 licks

Explanation:

murzikaleks [220]3 years ago

3 0

Answer: Around 364 to 480

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A 5.0 kg wooden block is placed at an adjustable inclined plane. what is the angle of incline above which the block will start t

Aleks [24]

The value of the angle of the incline $\theta$ at which the block starts to slide is the angle at which the component of the weight parallel to the incline becomes equal to the frictional force that keeps the block on the incline:
$mg \sin \theta = \mu N$
where the term on the left is the component of the weight parallel to the incline, and the term on the right is the frictional force, which is the product between the coefficient of friction $\mu$ and the normal reaction of the incline N.

The normal reaction of the incline, N, is equal to the component of the weight perpendicular to the incline:
$N=mg \cos \theta$
Therefore, the initial equation becomes
$mg \sin \theta = \mu mg \cos \theta$
From which we find
$\tan \theta = \mu$
$\theta = \arctan \mu$

For angles above this value, the block will start sliding down, otherwise the block will stay on the incline.

3 0

3 years ago

What are transverse waves and longitudinal waves have? how are they similar and different?

4vir4ik [10]

A transverse wave transfers energy perpendicular to the direction of wave motion. a longitudinal wave transfers energy parallel to the direction of the wave

3 0

3 years ago

What is true when an object is moved farther from a plane mirror?

musickatia [10]

Answer:

For a plane mirror, the image distance equals the object distance, so the image distance will increase as the object distance increases

The height of the image stays the same and the image distance increases.)

Explanation:

For plane mirrors, the object distance (is equal to the image distance. That is the image is the same distance behind the mirror as the object is in front of the mirror. If you stand a distance of 2 meters from a plane mirror, you must look at a location 2 meters behind the mirror in order to view your image

8 0

3 years ago

A 0.25 kg ball is suspended from a light 0.65 m string as shown. The string makes an angle of 31° with the vertical. Let U = 0 w

steposvetlana [31]

Explanation:

a) The height of the ball h with respect to the reference line is

$h = L - L\cos{31°} = L(1 - \cos{31°})$

so its initial gravitational potential energy $U_0$ is

$U = mgh = mgL(1 - \cos{31°})$

$\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})$

$\:\:\:\:\:=0.23\:\text{J}$

b) To find the speed of the ball at the reference point, let's use the conservation law of energy:

$\Delta{K} + \Delta{U} = 0 \Rightarrow K_0 + U_0 = K + U$

We know that the initial kinetic energy $K_0,$ as well as its final gravitational potential energy $U$ are zero so we can write the conservation law as