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kifflom [539]
4 years ago
9

For a normal eye, the near point is 25.0 cm. This is where you would like to place printed material such as the newspaper to rea

d. The far point is very far away. (a) What type and focal length corrective contact lens should a nearsighted person whose far point is 80.0 cm wear? What is the power of this lens? (b) What type and focal length corrective contact lens should a should a farsighted person wear if the person's near point is 60.0 cm away? What is the power of this lens?
Physics
1 answer:
JulijaS [17]4 years ago
4 0

Answer:

power is - 1.25 D

focal length is 0.429 m

power is 2.33 D

Explanation:

given data

near point  = 25.0 cm

far point  q = 80.0 cm

to find out

What type and focal length  for far point = 80.0 cm and near point = 60.0 cm away

solution

we apply here lens formula for concave lens

1/f = 1/p + 1/q

here we know p is infinity because near sight and q is negative i.e -80

1/f = 0 - 1/80

f = -80 cm

and power = 1/f

power = 1/80 = 0.0125 cm^{-1}

power = - 1.25 D

and

for far sight convex lens formula use

1/f = 1/p + 1/q

here p is 25 and q = -60

so 1/f = 1/25 - 1/60

1/f =  0.02333 cm^{-1}

f = 42.863 cm = 0.429 m

power = 1/f = 2.33 D

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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2>

\huge\boxed{OptionA}

<h2>_____________________________________</h2><h2>DATA:</h2><h3>Blue Car: </h3>

mass = 4 kg

velocity = 5 m/s^2

<h3 /><h3>Orange truck:</h3>

Mass= 2kg

Velocity = 7m/s^2

<h3 /><h3>Grey Car:</h3>

mass = 6 kg

velocity = 4m/s^2

<h3 /><h3>Green Car:</h3>

Mass = 8 kg

Velocity = 3 m/s^2

<h2>_____________________________________</h2><h2>SOLUTION:</h2>

By the equation of kinetic energy,

                                       

                                         K.E = \frac{1}{2} mv^2

Where,

            K.E is kinetic energy

            m is mass

            v is velocity

<h2>_____________________________________</h2><h3>Kinetic energy of Blue car:</h3>

 

Directly substitute the variables in the equation,

                                       

                                       K.E = \frac{1}{2}x4x5^2

Simplify the equation,

                                       K.E = 50 J

<h2>_____________________________________</h2><h3>Kinetic Energy of Silver Car:</h3>

                                           

 Directly substitude the variable in the equation,

                                                           

                                        K.E = \frac{1}{2}x6x4^2

Simplify the equation,

                                        K.E = 48J

<h2>_____________________________________</h2><h3>Kinetic Energy of Green Car:</h3><h3 />

Substitute the variables in the equation,

                                         

                                         K.E = \frac{1}{2}x8x3^2

Simplify the Equation,

                                         

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                                        K.E = 49J

<h2>_____________________________________</h2>

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