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Ksivusya [100]
3 years ago
13

1. Traditionally, only parties to a contract had rights and liabilities under the contract. This was known as the principle of _

__.
2. Match the term with the correct definition.

Assignment Transferring
all of the duties arising under a contract to another person
Delegation Transferring all the rights arising under a contract to another person
Physics
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

Privity of contract, Assignment

Explanation:

Privity of contract  is the relationship that exist between the parties to a contract which allows them to sue each other meanwhile it prevents a third party from doing so. It is a common law principle which provides that a contract cannot confer rights or impose obligations upon any person who is not a part to the contract.

<u>Assignment:</u> This is the act of transferring all or part of one's rights arising under a contract to another another person.

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A cell phone weighing 80 grams is flying through the air at 15 m/s what is the kinetic energy
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Answer:

9\:\mathrm{J}

Explanation:

Kinetic energy is given by the following equation:

KE=\frac{1}{2}mv^2, where m is mass in \mathrm{kg} and v is velocity in \mathrm{m/s}.

Since the cell phone's mass is given in grams, we need to convert this into kilograms:

80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}.

Therefore, the kinetic energy of the cell phone is:

KE=\frac{1}{2}\cdot 0.08\cdot 15^2=\fbox{$9\:\mathrm{J}$}.

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Answer:

The surface gravity g of the planet is 1/4 of the surface gravity on earth.

Explanation:

Surface gravity is given by the following formula:

g=G\frac{m}{r^{2}}

So the gravity of both the earth and the planet is written in terms of their own radius, so we get:

g_{E}=G\frac{m}{r_{E}^{2}}

g_{P}=G\frac{m}{r_{P}^{2}}

The problem tells us the radius of the planet is twice that of the radius on earth, so:

r_{P}=2r_{E}

If we substituted that into the gravity of the planet equation we would end up with the following formula:

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Which yields:

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So we can now compare the two gravities:

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When simplifying the ratio we end up with:

\frac{g_{P}}{g_{E}}=\frac{1}{4}

So the gravity acceleration on the surface of the planet is 1/4 of that on the surface of Earth.

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