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svet-max [94.6K]
2 years ago
13

The figure below shows two forces A=15 N and B=5 N acting on an object. What is the

Physics
1 answer:
alexandr1967 [171]2 years ago
7 0

Answer:

18.03 N

Explanation:

From the fiqure below,

Using parallelogram law of vector

R² = 15²+5²-2×5×15cos(180-60)

R² = 225+25-150cos120°

R² = 250-150(-0.5)

R² = 250+75

R² = 325

R = √325

R = 18.03 N

Hence the resultant force of the object is 18.03 N

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A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acc
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The acceleration of the crate after it begins to move is 0.5 m/s²

We'll begin by calculating the the frictional force

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Normal reaction (N) = mg = 50 × 10 = 500 N

<h3>Frictional force (Fբ) =?</h3>

Fբ = μN

Fբ = 0.15 × 500

<h3>Fբ = 75 N</h3>

  • Next, we shall determine the net force acting on the crate

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<h3>Net force (Fₙ) =?</h3>

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  • Finally, we shall determine the acceleration of the crate

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