<span>In order to determine the wavelength, we use the wave equation:
speed = frequency * wavelength
speed of light c = 3 x 10</span>⁸<span> m/s
Frequency f = 104.1 MHz = 1.041 x 10</span>⁸ Hz<span>
c = f</span>λ
λ = c / f
λ = 3 x 10⁸ / 1.041 x 10⁸
λ = 2.88 meters
The wavelength of the waves is 2.88 meters.
Answer:
t = √2y/g
Explanation:
This is a projectile launch exercise
a) The vertical velocity in the initial instants (
= 0) zero, so let's use the equation
y =
t -1/2 g t²
y= - ½ g t²
t = √2y/g
b) Let's use this time and the horizontal displacement equation, because the constant horizontal velocity
x = vox t
x = v₀ₓ √2y/g
c) Speeds before touching the ground
vₓ = vox = constant
=
- gt
= 0 - g √2y/g
= - √2gy
tan θ = Vy / vx
θ = tan⁻¹ (vy / vx)
θ = tan⁻¹ (√2gy / vox)
d) The projectile is higher than the cliff because it is a horizontal launch
1 point energy should be the answer
Answer:D
Explanation:Electric power=I*I*R
=12*12*100
=14400watts