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Soloha48 [4]
2 years ago
13

Domain and range What’s the domain and range of {(-4,2), (2,-4), (1,2), (-1,-7)}

Mathematics
1 answer:
dsp732 years ago
4 0
Domain (-4,2,1,-1)
Range(2,-4,-7)
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. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
Use the digits 3,7,1 and 5 to write a number that rounds to 1,700
Hitman42 [59]
To how many sig figs or decimal places? Could use 1735 if rounded to 2 significant figures (2sf)
5 0
3 years ago
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Find g(1) if g(x) =x^2+1​<br>A.4<br>B.2<br>C.3
kodGreya [7K]

Answer:

B.2

Step-by-step explanation:

g(1) if g(x) =x^2+1

= x^2 + 1 = (1)^2 + 1 = 1 + 1 = 2

8 0
2 years ago
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Question 9, literally almost done
AysviL [449]

Answer:

A 4

Step-by-step explanation:

2(3)=6-2=4

3 0
3 years ago
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Mrs. Chan, the P.E. teacher, is pairing off students to race against each other. Tracy can run 4 yards per second, and Alice can
NeTakaya

Answer:

21 yards in 3 seconds

Step-by-step explanation:

we give tracy the head start of 12 yards

then see how much she increases in 3 seconds at every second .

one second shes at 16 yards, 2 seconds she's at 20 yards & thats all the info we need

Alice runs 7 yards per second & we give her 3 seconds & how many yards she runs every second.

one second 7 yards , 2 seconds 14 yards & 3 seconds 21 yards & its at the 3 second that Alice has passed her.

3 0
3 years ago
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