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damaskus [11]
3 years ago
9

A device experiences a voltage drop of 5.0 V across it while a current of 10.0 mA flows through it. How much power does it dissi

pate? Show all work and include units of measure.
Physics
1 answer:
Kipish [7]3 years ago
4 0

Answer:

0.05 W

Explanation:

The power dissipated by a device can be written as

P=VI

where

P is the power dissipated

V is the voltage drop on the device

I is the current flowing through the device

In this problem, we have

V = 5.0 V is the voltage drop across the device

I = 10.0 mA = 0.01 A is the current through it

By applying the formula, we find the power dissipated:

P=(5.0 V)(0.01 A)=0.05 W

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A car's bumper is designed to withstand a 5.04-km/h (1.4-m/s) collision with an immovable object without damage to the body of t
aleksklad [387]

Answer:

3420.39 N

Explanation:

Applying,

Fd = 1/2(mv²-mu²)................. Equation 1

Where F = force on the bumber, d = distance, m = mass of the car, v = final velocity, u = initial velocity.

make F the subject of the equation

F = (mv²-mu²)/2d............... Equation 2

From the question,

Given: m = 890 kg, v = 0 m/s (to rest), u = 1.4 m/s, d = 0.255 m

Substitute these values into equation 2

F = [(890×0²)-(890×1.4²)]/(2×0.255)

F = -1744.4/0.51

F = -3420.39 N

The negative sign denotes that the force in opposite direction to the motion of the car.

5 0
3 years ago
I need help with this​
insens350 [35]

Answer:

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Explanation:

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7 0
3 years ago
An engineering intern is studying the effect of temperature on the resistance of a current carrying wire. She applies a voltage
Mars2501 [29]

Answer:

I=2.80 A

Explanation:

We Know that    R =R₀(1+∝ ΔT)

                           R=R₀ (1+3.9*10⁻³ *(61-20))

                           R=R₀ (1.1599)

                           I=V/R=V/(R₀ (1.1599)

                           1.4 = V/(R₀ (1.1599)                       ∵ equation 1

                     We have to calculate I when T=-88°

                              R =R₀(1+∝ ΔT)

                             R=R₀ (1+3.9*10⁻³ *(-88-20))

                             R=R₀ (0.5788)

                             I=V/(R₀ (0.5788)                          ∵equation 2

Dividing equation 2 by equation 1

                             \frac{I}{1.4} =\frac{1.1599}{0.5788}

                            I = 2.80 A

                         

4 0
3 years ago
Read 2 more answers
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