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3 years ago

What type of force cause an object to accelerate??

1 answer:

8 0

ANY force causes an object to accelerate, just as long as there are not
some other forces on the object that cancel out the first one.

Are you looking for the answer ... an "UNBALANCED" force ?
That's a very poor way to describe it, because there's no such thing
as a balanced or unbalanced force. The thing that's balanced or
unbalanced is a GROUP of forces, not a single force.

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In the picture of a planet in orbit around its star area a is double that of area b. What is true of the time the planet takes t

aalyn [17]

The Kepler's laws predict the planetary motion, so there are three laws for this, namely:

1. The orbit of a planet is an ellipse with the Sun (the sun is a star!) at one of the two focus.

2. A line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time.

3. The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit.

So, let's use second law. The Sun sweeps out equal areas during equal intervals of time means that if A = B, the time the planet takes to travel A1A2 is equal to the time the planet takes to travel B1B2, but given that A = 2B, then takes twice the time to travel A1A2 compared to B1B2.

8 0

3 years ago

Assume that the electric field E is equal to zero at a given point. Does it mean that the electric potential V must also be equa

lyudmila [28]

Answer:

No, this doesn't mean the electric potential equals zero.

Explanation:

In electrostatics, the electric field $\vec{E}$ is related to the gradient of the electric potential V with :

$\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r})$

This means that for constant electric potential the electric field must be zero:

$V(\vec{r}) = k$

$\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r}) = - \vec{\nabla} k$

$\vec{E} (\vec{r}) = - (\frac{\partial}{\partial x} , \frac{\partial}{\partial y } , \frac{\partial}{\partial z}) k$

$\vec{E} (\vec{r}) = - (\frac{\partial k}{\partial x} , \frac{\partial k}{\partial y } , \frac{\partial k}{\partial z})$

$\vec{E} (\vec{r}) = - (0,0,0)$

This is not the only case in which we would find an zero electric field, as, any scalar field with gradient zero will give an zero electric field. For example:

$V(\vec{r})= (x+2)^2 (y+4)^3 (z+5)^4$

give an electric field of zero at point (0,0,0)

8 0

3 years ago

Racewalking involves more impact than running. true false

natta225 [31]

I think the statement is false. Racewalking involves less impact than running. It <span> is a long-distance discipline within the sport of athletics. Although it is a foot race, it is different from running in that one foot must appear to be in contact with the ground.</span>

5 0

3 years ago

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There are 3.3V passing through an orange power supply cable, and there are 0.025 ohms of resistance in the orange wire. How much

PIT_PIT [208]

P = V^2 / R.

So, 3.3^2 / 0.025 = 435.6W.

Note, you can get the power equation from:
P = V*I. Also, I = V/R.
Substituting V/R in for I in the 1st equation, you get P = V^2 / R.

5 0

3 years ago

The modern periodic table has______ groups. (Write your answer as a number.)

kobusy [5.1K]

It contains 18 groups

4 0

3 years ago

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