1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vladimir1956 [14]
3 years ago
10

What type of force cause an object to accelerate??

Physics
1 answer:
Olin [163]3 years ago
8 0
ANY force causes an object to accelerate, just as long as there are not
some other forces on the object that cancel out the first one.

Are you looking for the answer ... an "UNBALANCED" force ?
That's a very poor way to describe it, because there's no such thing
as a balanced or unbalanced force.  The thing that's balanced or
unbalanced is a GROUP of forces, not a single force.
You might be interested in
Which of the following are simple machines?<br> Select all that apply.
scoundrel [369]

Answer:

where is option

you only say choose that following select apply

Explanation:

please give option

5 0
2 years ago
Read 2 more answers
A MEMS-based accelerometer has a mass of m = 2 grams, an equivalent spring constant of k = 5 N/m, and an equivalent damping coef
pychu [463]

Answer:

The natural frequency = 50 rad/s = 7.96 Hz

Damping ratio = 0.5

Explanation:

The natural frequency is calculated in this manner

w = √(k/m)

k = spring constant = 5 N/m

m = mass = 2 g = 0.002 kg

w = √(5/0.002) = 50 rad/s

w = 2πf

50 = 2πf

f = 50/(2π) = 7.96 Hz

Damping ratio = c/[2√(mk)] = 0.1/(2 × √(5 × 0.002)) = 0.5

5 0
3 years ago
A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The
Goshia [24]

Answer:

0.629\ \text{rad/s}^2 counterclockwise

9.98\ \text{s}

Explanation:

r_1 = Small drive wheel radius = 2.2 cm

\alpha_1 = Angular acceleration of the small drive wheel = 8\ \text{rad/s}^2

r_2 = Radius of pottery wheel = 28 cm

\alpha_2 = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2

The angular acceleration of the pottery wheel is 0.629\ \text{rad/s}^2.

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}

t = Time taken

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}

The time it takes the pottery wheel to reach the required speed is 9.98\ \text{s}

4 0
3 years ago
Each wheel of a 320 kg motorcycle is 52 cm in diameter and has rotational inertia 2.1 kg m2 . The cycle and its 75 kg rider are
Amiraneli [1.4K]

Answer:

The value is  h  = 32.91 \  m

Explanation:

From the question we are told that

    The diameter of each wheel is  d =  52 \ cm  =  0.52 \  m

    The mass of the motorcycle is  m  =  320 \ kg

    The rotational kinetic inertia is  I  =  2.1 \  kg \  m^2

    The  mass of the  rider is  m_r =  75 \ kg

     The  velocity is  v  =  85 \  km/hr = 23.61 \  m/s

      Generally the radius of the wheel is mathematically represented as

      r =  \frac{d}{2}

=>     r =  \frac{0.52}{2}

=>    r =  0.26 \  m

Generally from the law of energy conservation

     Potential energy  attained  by  system(motorcycle and rider )  =  Kinetic  energy of the system  +  rotational kinetic energy of  both wheels of the motorcycle

=>  Mgh  =  \frac{1}{2}  Mv^2  +   \frac{1}{2}  Iw^2  +  \frac{1}{2}  Iw^2

=>    Mgh  =  \frac{1}{2}  *  Mv^2  +  Iw^2

Here  w is the angular velocity which is mathematically represented as

     w =  \frac{v }{r }

So

    Mgh  =  \frac{1}{2}  *  Mv^2  +  I \frac{v}{r} ^2

Here M  =  m_r +  m

         M  =  320 + 75

          M  = 395 \  kg

395 *  9.8 *  h  =   0.5    *   395 *  (23.61)^2 +  2.1  *[\frac{ 23.61}{ 0.26} ] ^2

=>   h  = 32.91 \  m

   

7 0
4 years ago
A shot putter shoots a 7.3kg shot from rest to 14m/s in 1.5s. what was the average power?
sweet [91]

Answer: 477W

Explanation:

Given the following :

Mass (m) = 7.3kg

Initial Velocity (u) = 0

Final velocity (v) = 14m/s

time (t) = 1.5s

Power = workdone (W) / time (t)

The workdone can be calculated as the change in kinetic energy (KE) :

Recall ;

KE = 0.5mv^2

Therefore, change in KE is given by:

0.5mv^2 - 0.5mu^2

Change in KE = 0.5(7.3)(14^2) - 0.5(7.3)(0^2)

Change in KE = 715.4J

Therefore ;

Average power = Workdone / time

Workdone = change in KE = 715.4N

Average power = 715.4 / 1.5

Average power = 476.93333 W

= 477W

5 0
4 years ago
Other questions:
  • Does a force cause motion or a change in motion
    6·1 answer
  • While moving in, a new homeowner is pushing a box across the floor at a constant velocity. The coefficient of kinetic friction b
    10·1 answer
  • What two units of measurement are necessary for describing speed
    8·1 answer
  • A block of mass m=9.0 kg and speed V and is behind a block of mass M= 27 kg and speed of .50 m/s. The surface is frictionless, a
    14·1 answer
  • An ambulance driver traveling at 31.0 m/s (69.3 mph) honks his horn as he sees a motorist ahead on the highway traveling in the
    13·1 answer
  • In the Bohr model of the hydrogen atom, the electron moves in a circular orbit of radius 5.3×10−11m with a speed of 2.2×106m/s.
    15·1 answer
  • What is a scientific paradigm
    13·1 answer
  • The 5.00-cm-long second hand on a watch rotates smoothly. What is its angular velocity?
    6·1 answer
  • Our Sun is an example of a main sequence star. Outline the two factors that keep a main
    5·2 answers
  • If you blow air between a pair of closely-spaced Ping-Pong balls suspended by strings, the balls will swing
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!