Let x and y be the unknown numbers.
x + y = 5
xy = 24
x + y = 5
y = 5-x
xy = 24
x(5-x) = 24
5x - x² = 24
- x² + 5x -24 = 0
(a <u>+</u> √a² - 4b)/2
(5 <u>+</u> √5² - 4(-24))/2
(5 <u>+</u> √25 + 96)/2
(5 <u>+</u> √121)/2
(5 + 11)/2 ; (5 - 11)/2
16/2 -6/2
8 ; -3
Answer:
~114.56
Step-by-step explanation:
Because you're asked to find the number so that x% is y, we will have to find that number. The equation in that case would be NUM * 0.934 = 107. Divide both sides by .934 to get an answer of approximately 114.56.
Answer:
Hey there!
Left 2 units: (7,-2)
Down 1 unit: (7, -3)
Final answer: (7, -3)
Let me know if this helps :)
Answer:
We need to contact 542 employees.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
98% confidence level
So , z is the value of Z that has a pvalue of , so .
a) How many randomly selected employers must we contact in order to create an estimate in which we are 98% confident with a margin of error of 5%
We dont know the proportion, so we use , which is when we are going to need the largest sample size.
We have to find n when M = 0.05. So
Rounding up
We need to contact 542 employees.
<span>200 < 225 + 80x < 550
The 200 is the amount the Jenna currently have.
225 + 80x is the amount that Jenna has to pay given x number of hours.
550 is the sum of Jenna's 200 and additional 350 she can get by selling pre-ordered Cds. This is the maximum amount she can pay for the studio rental and sound technicians.
225 + 80x < 550
80x < 550 -225
80x < 325
80x / 80 < 325/80
x < 4.06 or 4 hours
225 + 80x </span>→ 225 + 80(4) = 225 + 320 = 545
<span>
The number of hours for the sound technician will range from 1 hour to 4 hours.
Assuming they will use 6 hours.
225 + 80(6) = 225 + 480 = 705
705 - 550 = 155
Jenna has to raise an additional $155 to pay off the studio rent and 6 hours of sound technicians.
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