All categories

3 years ago

Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 405 mL .

1 answer:

7 0

In this question, you are given the density (2.7g/ml) and the volume of the aluminum. You are asked how much the volume is. To answer this question, you need to convert the volume into mass. Since the unit used is already same, you don't need to convert it into another unit. The calculation would be:

mass= volume / density
mass= 405ml / (2.70 g/ml)
mass= 150grams

You might be interested in

CH3-CHCl-CH2-CH2-CH2CHCl-CH3 +concentrated KCN

Phantasy [73]

Is this chemistry or something else?

8 0

3 years ago

Read 2 more answers

HELPP! pls

pshichka [43]

Answer:

"2.48 mole" of H₂ are formed. A further explanation is provided below.

Explanation:

The given values are:

Mole of Al,

= 3.22 mole

Mole of HBr,

= 4.96 mole

Now,

(a)

The number of mole of H₂ are:

⇒ $\frac{Mole \ of \ H_2}{3} =\frac{Mole \ of HBr}{6}$

or,

⇒ $Mole \ of \ H_2=\frac{1}{2}\times Mole \ of \ HBr$

⇒ $=\frac{1}{2}\times 4.96$

⇒ $=2.48 \ mole$

(b)

The limiting reactant is:

= $HBr$

(c)

The excess reactant is:

= $Al$

6 0

2 years ago

What are the four factors that affect the natural selection?

BaLLatris [955]

Answer:

• potential for a species to increase in number

• the heritable genetic variation/ which results from mutation in dna

• the size of a population increases

• competiton for resources that are limited in that specific environment.

Explanation:

these are all factors that would affect natural selection although there are many more.

6 0

3 years ago

If 4.12 l of a 0.850 m-h3po4 solution is be diluted to a volume of 10.00 l, what is the concentration of the resulting solution?

statuscvo [17]

The process in which the concentration of the solution is lessened by the addition of water is said to be dilution and equation of dilution relates the initial concentration and volume of stock solution with the final concentration and volume of the solution.

Formula is given by:

$C_{1}V_{1}=C_{2}V_{2}$ (1)