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VikaD [51]
4 years ago
11

What is the electronic configuration of Au3+?

Chemistry
1 answer:
Anettt [7]4 years ago
4 0

Answer:

AU^{3+} : [Rn] 5f^3

Explanation:

Writing electronic configuration of any element you should know atomic number of that element ,

and also electrons are filling according to their energy level and first electron is filled in the lower energy orbital

and it follows n+1 rule if n+1 is same for two orbital electron will go first in the lowest value of n.

writing electronic configuration of ion can be done like first for their neutral atom and then add or remove electron it will make things easy because there are also some eception case their you may do wrong.

AU : [Rn] 5f^3 6d^1 7s^2

remove three electron from outer most shell of AU

AU^{3+} : [Rn] 5f^3

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The exhaust gas from an automobile contains 1.5 percent by volume of carbon monoxide. What is the concentration of CO in mg/m' a
FrozenT [24]

Answer:

(a) 17,178 mg/m3

(b) 11,625 mg/m3

Explanation:

The concentration of CO in mg/m3 can be calculated as

C (mg/m3) =(P/RT)*MW*C_{ppm}

For standard conditions (1 atm and 25°C), P/RT is 0.0409.

Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.

The molecular weigth of CO is 28 g/mol.

(1) For 25°C and 1 atm conditions

C=(P/RT)*MW*C_{ppm}\\\\C=0.0409*28*15,000=17,178

(b) For 200°C and 1.1 atm,

P/RT=0.0409*(P/P_{std})*(T_{std}/T)\\P/RT=0.0409*(1.1atm/1atm)*(273+15K/273+200K)=0.0277

Then the concentration in mg/m3 is

C=(P/RT)*MW*C_{ppm}\\\\C=0.0277*28*15,000=11,625

5 0
3 years ago
What is the correct balanced equation for the following:
Romashka [77]
A)
K has a positive charge of 1
I has a negative charge of 1
S has a negative charge of 2
Pb has a positive charge of 2

2KI + PbS —> PbI2 + K2S
5 0
3 years ago
The Mole #2<br> Avogadro's Number <br> PLEASE HELP ASAP! due tmr will give brainliest!
Elis [28]

The solution is here,

given mass of copper wire(m)=25 g

no. of moles in given mass of Cu=0.393

a) no. of atoms= no. of moles×avogardo's number

=0.393×6.023×10^23=2.36 ×10^23 atoms

b) 25 g of Cu wire has 0.393 moles

so 200 g of Cu wire has 0.393/25 × 200=3.144 mol.

no. of atoms= 3.144×2.023×10^23=1.89×10^24 atoms.

c) 25 g of Cu wire has 2.36×10^23 atoms

so 5 g of Cu wire has (2.36×10^23)/25 × 5

=4.72×10^22 atoms

( b can also be solve like c)

7 0
3 years ago
Calculate the mass of water if the densityis 1.02 g/mL and the volume is 62 ml. M = (D(V)
schepotkina [342]

Answer:

<h2>The answer is 63.24 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 62 mL

density = 1.02 g/mL

The mass of the water is

mass = 1.02 × 62

We have the final answer as

<h3>63.24 g</h3>

Hope this helps you

7 0
3 years ago
If you drop soap on the floor is the soap dirty or is the floor clean?
tia_tia [17]

Answer:

hahahaha the soappp is dirty and the floor gets clean

6 0
3 years ago
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