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VikaD [51]
3 years ago
11

What is the electronic configuration of Au3+?

Chemistry
1 answer:
Anettt [7]3 years ago
4 0

Answer:

AU^{3+} : [Rn] 5f^3

Explanation:

Writing electronic configuration of any element you should know atomic number of that element ,

and also electrons are filling according to their energy level and first electron is filled in the lower energy orbital

and it follows n+1 rule if n+1 is same for two orbital electron will go first in the lowest value of n.

writing electronic configuration of ion can be done like first for their neutral atom and then add or remove electron it will make things easy because there are also some eception case their you may do wrong.

AU : [Rn] 5f^3 6d^1 7s^2

remove three electron from outer most shell of AU

AU^{3+} : [Rn] 5f^3

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Answer:

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

Explanation:

The balanced equation for the reaction between silicon dioxide and carbon at high temperature is given as:

SiO_2+3C\rightarrow SiC+2CO

1 mole silicon dioxide reacts with 3 moles of carbon to give 1 moles of silicon carbide and 2 moles of carbon monoxide.

Mass of SiC = 3.00kg = 3000.00 g

1 kg = 1000 g

Molecular mass of SiC = 40 g/mol

Moles of SiC = \frac{3000.00 g}{40 g/mol}= 75 mol

According to reaction, 1 mole of SiC is produced from 1 mole of silicon dioxide.

Then 75 moles of SiC will be produce from:

\frac{1}{1}\times 75 mol=75 mol of silicon dioxide.

mass of 75 moles of silicon dioxde:

75 mol\times 60 g/mol=4500 g=4.5 kg

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

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