Answer:

Explanation:
The pressure is constant, so we can use Charles' Law to calculate the volume.

Data:
V₁ = 693 mL; T₁ = 45 °C
V₂ = ?; T₂ = 150 °C
Calculations:
(a) Convert temperature to kelvins
T₁ = ( 45 + 273.15) = 318.15 K
T₂ = (150 + 273.15) = 423.15 K
(b) Calculate the volume

Answer:
82.97 K
Explanation:
Applying,
PV/T = P'V'/T'................ Equation 1
Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.
Make T' the subject of formula in equation 1
T' = P'V'T/PV................ Equation 2
From the question,
Given: P = 877 mmHg = (877×0.001316) atm = 1.154 atm, T = 222.2 K, V = 7.9 L, P' = 0.327 atm, V' = 10.41 L
Substitute these values into equation 2
T' = (0.327×10.41×222.2)/(1.154×7.9)
T' = 82.97 K
Hence the new temperature is 82.97 K
Answer:
The unfiltered polluted water is not clear and is yellowish in color. The filtered polluted water is clear with a little bit of yellow color. The pH readings are beyond the range in which organisms can grow. Based on these observations, I can conclude that even though water may look clean, it could actually not be clean or it can still be harmful to living things.
To explore the use of punnett square to predict genotype and phenotypes of offsprings an investigation must be conducted
Answer:
Oxidation number of each atom in sodium hydrogen carbonate ( NaHCO3) are
Na = +1
H = +1
C = +4
O = -2
Explanation:
Let's pick the first atom
NaHCO3
find oxidation number of Na
Na + 1 +4 + 3(-2) = 0( because there is no charge)
Na + 5 - 6 = 0
Na = 6 -5
Na = +1
Always put the sign
Find the oxidation number of H in NaHCO3
+1 + H + 4 + 3(-2) = 0.
H + 1 + 4 + 3(-2) = 0
H + 5 -6 = 0
H = 6 -5
H = +1
Find the oxidation number of C In NaHCO3
+1 +1 +C + 3(-2) = 0
C + 1+1-6 = 0
C +2 - 6= 0
C = 6 -2
C = +4
Find the oxidation number of O in NaHCO3
+1 + 1 + 4 + 3(O) = 0
6 + 3 (O) = 0
3(O) = -6
Divide through by 3 to get O
3(O) / 3 = -6 / 3
O = -6/3
O = -2