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geniusboy [140]
3 years ago
11

How many moles of O2 are needed to burn 2.56 moles of CH3OH?

Chemistry
1 answer:
lukranit [14]3 years ago
6 0

Answer:

n_{O_2}=3.84molO_2

Explanation:

Hello!

In this case, since the combustion reaction of methanol is:

CH_3OH+\frac{3}{2} O_2\rightarrow CO_2+2H_2O

In such a way, since there is 1:3/2 mole ratio between methanol and oxygen, we can compute the moles of oxygen that are needed to burn 2.56 moles of methanol as shown below:

n_{O_2}=2.56molCH_3OH*\frac{\frac{3}{2}molO_2}{1molCH_3OH} \\\\n_{O_2}=3.84molO_2

Best regards!

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