Maybe molecules one electron
Given what we know, we can confirm that the amount of heat energy that would be required in order to boil 5.05g of water is that of 11.4kJ of heat.
<h3>Why does it take this much energy to boil the water?</h3>
We arrive at this number by taking into account the energy needed to boil 1g of water to its vaporization point. This results in the use of 2260 J of heat energy. We then take this number and multiply it by the total grams of water being heated, in this case, 5.05g, which gives us our answer of 11.4 kJ of energy required.
Therefore, we can confirm that the amount of heat energy that would be required in order to boil 5.05g of water is that of 11.4kJ of heat.
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Answer:
0.857 atm
Explanation:
The nitrogen stops owing when it fulfills both of the tanks (the gas molecules intend to fulfill all the space they are). So the tanks will have the same pressure, and the final volume will be the volume of the two tanks.
For Boyle's law:
P1*V1 = P2*V2
Where P1 is the initial pressure (3.00 atm), V1 is the initial volume(2.00 L), P2 is the final pressure, and V2 is the final volume (2.00 + 5.00 = 7.00 L).
3.00*2.00 = P2*7.00
7.00P2 = 6.00
P2 = 0.857 atm
Answer:
4.09ₓ10²³ atoms are contained in 10g of C₃H₈
Explanation:
1 mol of C₃H₈ has 3 mol of carbon and 8 mol of hydrogen.
1 mol of C₃H₈ weighs 44 g
In 44 g of C₃H₈ we have 3 mol of C
In 10 g of C₃H₈ we'll have (10 . 3)/ 44 = 0.681 mol
1 mol of C has NA (6.02x10²³) particles
0.681 mol will have (0.681 . 6.02x10²³) = 4.09ₓ10²³ atoms
