A fleet of nine taxis is to be dispatched to three airports in such a way that three go to airport A, five go to airport B, and one goes to airport C. In how many distinct ways can this be accomplished?
2.44) Refer to Exercise 2.43. Assume that taxis are allocated to airports at random.
a) If exactly one of the taxis is in need of repair, what is the probability that it is dispatched to airport C?
b) If exactly three of the taxis are in need of repair, what is the probability that every airport receives one of the taxis requiring repairs?
So, my answer to 2.44a is 1/9. Hopefully this is correct at least :)
For 2.44b, my guess was
(3C1)(1/3)(2/3)2 * (5C1)(1/3)(2/3)4 * 1/3
The solutions manual on chegg (which seems to be riddled with errors) says something completely different. Is my calculation correct?
I do not see an answer, only because Zach's change in reading time increases exponentially, and Victoria's increases at a linear rate.
The LCM is 2, Because 2*4=8 and 2*50=100 :)
Week one:
36 * 6.70 = $241.20
Week two:
40 * 6.85 = $274
Subtract:
274 - 241.20 = $32.80
Therefore, he made $32.80 more the second week then he did the first week.
Best of Luck!
You need to add both numbers and then that's your answer 6-6/12
