The balanced chemical reaction is written as:
2K + F2 = 2KF
We are given the amount of potassium to be used in the reaction. THis will be the starting point. We do as follows:
23.5 g K ( 1 mol / 39.10 g) (1 mol F2 / 2 mol K ) ( 22.4 L / 1 mol ) = 6.73 L F2 gas needed
A I don’t know how to explain it but I just know that it’s A
I believe it is a(n) independent variable
i could be wrong sorry<span />
Answer:
The answer to your question is molality = 0.34
Explanation:
Data
mass of NaBr = 14.57 g
mass of water = 415 g.
molality = ?
Process
1.- Calculate the molar mass of NaBr
NaBr = 23 + 80 = 103 g
2.- Calculate the moles of NaBr
103 g of NaBr ------------------ 1 mol
14.57 g of NaBr --------------- x
x = (14.57 x 1) / 103
x = 14.57 / 103
x = 0.141 moles
3.- Calculate the molality
molality = moles / volume
-Substitution
molality = 0.141 / .415
-Result
molality = 0.34
<span>Mn(HPO4)2 - managanese (II) monohydrogen phosphate ion</span>