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Leviafan [203]
3 years ago
10

A fertilized egg cell develops into a(n) _________

Chemistry
1 answer:
Inessa [10]3 years ago
5 0
I THINK it is d if it’s wrong i’m so sorry
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FIRST GETS BRAINLIEST (THE ONE THAT IS CORRECT)
andrew11 [14]

Answer:

mechanical energy to electrical energy

Explanation:

The water turns the turbine with produces mechanical energy so the generator converts it to electrical energy

4 0
3 years ago
Consider the molar solubility of SrCO3 in 0.10 M Sr(NO3)2 versus in pure water. Ksp SrCO3 = 5.4 x 10-10 Which statement is true?
lesya692 [45]

Answer:

The molar solubility of SrCO3 will be lower in 0.10 M 0 M Sr(NO3)2 because of Sr2+

Explanation:

The question reflects the phenomenon known in chemistry as common ion effect. Common ion effect refers to the decreased solubility of a solid in a solution that contains an ion in common with the solute.

In the case of our example here, both strontium carbonate and strontium nitrate possess the strontium II ion in common. The presence of this ion in strontium nitrate will decrease the solubility of strontium carbonate in accordance with Le Chateliers principle. Hence the answer.

8 0
2 years ago
Pilots often use waves of about 2.340m to communicate. what is the frequency of the wave ?why?
uranmaximum [27]

All of the various light waves move with the same speed, a value

<span>abbreviated (c) equal to 3.00 × 108 m/s. The frequency ([1]) that light waves pass a given point is</span>

measured in waves/second or simply ‘per second’ (1/s).

the frequency of the wave f = (3.00 × 10^8 m/s)/ 2.340 m

<span>f = 1.28x10^8 Hz</span>

3 0
2 years ago
PLEASE HELP!!!!!
Blababa [14]
It would be water. Since the body is 60-75% water, it is important in chemical reactions within the body.
4 0
3 years ago
A 10.00 g sample of a soluble barium salt is treated with an excess of sodium sulfate to precipitate 11.21 g BaSO4 (M- 233.4). W
aliina [53]

Answer:

The salt is barium chloride.

Explanation:

BaX_2++Na_2SO_4\rightarrow BaSO_4+2NaX

Moles of barium sulfate =\frac{11.21 g}{233.38 g/mol}=0.0480 mol

According to reaction, 1 mol of barium sulfate is produced from 1 mol of BaX_2.

Then 0.0480 moles will be produced from:

\frac{1}{1}\times 0.0480 mol=0.0480 mol of BaX_2.

Mass of BaX_2 used = 10.00 g

Moles of BaX_2 =\frac{10.00 g}{\text{Molar mass}}[/tex]

0.0480 mol=\frac{10.00}{\text{Molar mass}}

Molar mass of BaX_2 = 208.33 g/mol

The nearest answer to our answer is BaCl_2=208.2 g/mol.

The correct answer barium chloride with molar mass of 208.2 g/mol.

8 0
3 years ago
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