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Solnce55 [7]
1 year ago
9

An ion of a single pure element always has an oxidation number of ________. a. 1 b. magnitude equal to its atomic number c. 0 d.

none of these
Chemistry
1 answer:
harina [27]1 year ago
6 0

The oxidation state of a pure element is always zero.

The oxidation state for a pure ion is equivalent to its ionic charge.

What is oxidation state?

The oxidation state or oxidation number, is the hypothetical charge of an atom if all of its bonds to different atoms were fully ionic. The oxidation state may be positive, negative or zero.

What are the rules to write the oxidation number?

1. The atoms in pure elements have oxidation number of ZERO.

2. The more-electronegative element in a binary molecular compound is assigned the number equal to the negative charge it would have as an anion. The less-electronegative element is assigned the number equal to the positive charge it would have as a cation.

3. Fluorine always has an oxidation number of -1 in compounds because it is the most electronegative element.

4. Oxygen is usually -2 unless in peroxides (then it is -1) or with fluorine.

5. Hydrogen has +1 in all compounds containing elements that are more electronegative than it, and is -1 in compounds with metals.

6. The algebraic sum of the oxidation numbers of all atoms in a neutral compound is zero.

7. The algebraic sum of the oxidation numbers of all atoms in a polyatomic ion is equal to the charge of the ion.

8. Although rules 1-7 apply to covalently bonded atoms, oxidation numbers can also be assigned to atoms in ionic compound. Monoatomic ions have oxidation numbers equal to their ionic charge.

To learn more about oxidation number: brainly.com/question/3035498

#SPJ4

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Water (with density of 1000 kg/m3) with the mass flowrate of 10 kg/sec is flowing into an empty tank. The outlet volumetric flow
Montano1993 [528]

Explanation:

Apply the mass of balance as follows.

   Rate of accumulation of water within the tank = rate of mass of water entering the tank - rate of mass of water releasing from the tank

         \frac{d}{dt}(\rho V) = 10 - \rho \times (0.01 h)

      \rho A_{c} \frac{dh}{dt} = 10 - (0.01) \rho h

   \frac{dh}{dt} + \frac{0.01 \rho h}{\rho A_{c}} = \frac{10}{\rho A_{c}}

          [/tex]\frac{dh}{dt} + \frac{0.01}{0.01}h[/tex] = \frac{10}{\rho A_{c}}

                       A_{c} = 0.01 m^{2}

              \frac{dh}{dt} + h = 1

                  \frac{dh}{dt} = 1 - h

               \frac{dh}{1 - h} = dt  

                \frac{ln(1 - h)}{-1} = t + C      

Given at t = 0 and V = 0  

                         A \times h = 0  

 or,                     h = 0

                 -ln(1 - h) = t + C

Initial condition is -ln(1) = 0 + C

                                C = 0  

                So,   -ln(1 - h) = t

or,                      t = ln (\frac{1}{1 - h})  ........... (1)

(a)    Using equation (1) calculate time to fill the tank up to 0.6 meter from the bottom as follows.

                    t = ln (\frac{1}{1 - h})  

                     t = ln (\frac{1}{1 - 0.6})  

                        = ln (\frac{1}{0.4})

                        = 0.916 seconds

(b)   As maximum height of water level in the tank is achieved at steady state that is, t = \infty.  

                    1 - h = exp (-t)

                    1 - h = 0  

                         h = 1

Hence, we can conclude that the tank cannot be filled up to 2 meters as maximum height achieved is 1 meter.

                 

8 0
3 years ago
Which of the following statements below correctly describes the parts of an atom that determine the atom's identity and chemical
stich3 [128]

Answer:

B protons determine indentity and valence electrons determine chemical properties.

:)

Explanation:

6 0
3 years ago
a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre
zhannawk [14.2K]
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

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The final pressure exerted by the gas would be 0.593 torr.

Hope this helps!
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vovangra [49]

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The given reaction is exothermic. So, heat energy will be a product. Therefore, decreasing the temperature (heat energy) would lead to the formation of more products as when the amount of energy which is a product is reduced, there is more room for the products to form.

Increasing the pressure would shift the equilibrium towards that side which has least number of moles of the gaseous substance. Hence, here increasing the pressure would lead to the formation of more products by shifting the equilibrium towards the right side.

Decreasing the volume would make the equilibrium shift towards the least number of moles of the gaseous substance. So, here in this equilibrium decreasing the volume would lead to the formation of more products.

8 0
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Alecsey [184]
I think its potassium bromide
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3 years ago
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