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morpeh [17]
2 years ago
5

Need an answer for the question

Mathematics
1 answer:
inysia [295]2 years ago
4 0

Answer:

x = 8/13

Step-by-step explanation:

6 - 3x - 3/5(15x + 20) = 7(2x/7 - 2) - x

6 - 3x - 9x - 12 = 2x - 14 - x

6 - 12 + 14 = 2x - x + 3x + 9x

8 = 13x

x = 8/13

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River C is 300 Miles Longer than River D. If the sum of their lengths is 5,570 miles, what is the length of each river?
d1i1m1o1n [39]
x-\ length\ of\ river\ D\\
x+300-\ length\ of\ river\ C\\\\
5570=x+x+300\\
5570=2x+300\ \ \ | subtract\ 300\\5270=2x\ \ \ | divide\ by\ 2\\x=2635\\\\
River\ C\ is\ 2935miles\ long\ and\ river\ D\ 2635\ miles\ long.
6 0
3 years ago
15yd=45ft show the work to solve problem
disa [49]

Answer:

15 yd = 45 ft because :

Step-by-step explanation:

You have to multiply the length by 3.

1 yd = 3 ft.

15 x 3 = 45.

Hope this helps,

Davinia.

3 0
3 years ago
What is the slope of the line that passes through the points (-7, -7) and (-7, 1) ?
ICE Princess25 [194]

Answer:

undefined

Step-by-step explanation:

(-7, -7) and (-7, 1)

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Plug in these values:

(1 - (-7)) / (-7 - (-7))

Simplify the parentheses.

= (1 + 7) / (-7 + 7)

Simplify the fraction.

8/0

= undefined

Our line is a vertical line, which has an undefined slope.

Hope this helps!

6 0
3 years ago
select the correct answer you're getting two side lengths of 10 cm and 8 centimeters the angle between the sides measure 40° how
Readme [11.4K]

Answer:

Step-by-step explanation:

16 triangles

5 0
2 years ago
Read 2 more answers
The volume
Sedaia [141]
\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
&&  y={{ k }}x
\end{array}\\ \quad \\


and also

\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
&&y=\cfrac{{{  k}}}{x}
\end{array}


now, we know that V varies directly to T and inversely to P simultaneously
thus\bf V=T\cdot \cfrac{k}{P}

so     \bf V=T\cdot \cfrac{k}{P}\qquad 
\begin{cases}
V=42\\
T=84\\
P=8
\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k
\\\\\\
V=\cfrac{4T}{P}\qquad now\quad 
\begin{cases}
V=74\\
P=10
\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T
7 0
3 years ago
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