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4 years ago

A set of data is collected for objects in an inelastic collision, as recorded in the table.

Physics

2 answers:

Llana [10]4 years ago

6 0

Answer:

A body in motion has momentum. It is the product of mass and velocity.

To identify the momentum of object 1, we mus multiply B. mass and C. velocity.

Mass of object 1 is: 2.0 kg and velocity is 4.0 m/s

So, the momentum of the object 1 is:

P = m v

⇒ P = 2.0 kg × 4.0 m/s = 8.0 kg m/s

Thus, Object 1 had a momentum of C. 8.0 kg ∙ m/s before the collision.

Mass of Object 2: 6.0 kg

Velocity of object 2 = 0

Thus, Object 2 had a momentum of A. 0.0 kg.m/s before the collision.

Mass of object 3: 8.0 kg

velocity of object 3: 1.0 m/s

Momentum of object 3 before collision= 8.0 kg × 1.0 m/s = 8.0 kg.m/s

From law of conservation of momentum, initial momentum is equal to final momentum.

Initial momentum = (8 + 0 + 8) kg.m/s = 16.0 kg.m/s

Thus, the combined mass would have a total momentum = 16.0 kg.m/s after collision.

The combined mass ( 2+6+8 = 16 kg) would move with the velocity of:

v = P/m = (16.0 kg.m/s )/16 kg = 1 m/s after collision.

Finger [1]4 years ago

5 0

Momentum = Mass x Velocity

In a collision, the Total Momentum of the system is always conserved (stays the same.) To find the total momentum of the system just add the momentum of all the objects together.

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A force of 20.0 N is applied to a 3.00 kg object for 4.00 seconds. Calculate the impulse experienced by the object.

GenaCL600 [577]

Answer:

Impulse = 80Ns

Explanation:

Given the following data;

Mass = 3kg

Force = 20N

Time = 4 seconds

To find the impulse experienced by the object;

Impulse = force * time

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Impulse = 80Ns

Therefore, the impulse experienced by the object is 80 Newton-seconds.

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3 years ago

For a home sound system, two small speakers are located so that one is 52 cm closer to the listener than the other. For what val

Veseljchak [2.6K]

We want a sound wave with a wavelength of 0.52 meters or a natural fraction thereof. We'll work in MKS.

w = 0.52/n

That's length. We have speed 344 meters/second so w corresponds to a frequency of

f = 344 / w = n (344/.52)

f = 661.5 n Hertz

I don't really agree with how they're saying it, but all the fundamental talk is probably trying to tell us n=1,

Answer: 661.5 Hertz

Any multiple of that will also produce constructive interference; we can go to about n=30 before we're out of the audio range.

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3 years ago

In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x

Ostrovityanka [42]

Answer:

(a) increase

Explanation:

On a line graph; we have the x-axis to the positive side and the negative side .In a positive x-axis direction, the force is usually positive, vice versa the negative side as well.

The change in the potential energy of a charge field-system can be given as:

$\delta U= -q(EdsCos \theta)$

where;

q = positive test charge

E = Electric field

ds = displacement between thee charge positions

θ = Angle between the electric field and the displacement.

Given that:

Charge of the particle = -q

displacement = (60.0 -20.0)cm = 40.0 cm

θ = 0

Replacing our values in the above equation, we have:

$\delta U = -(-q)(60Cos 0)$

$\delta U = qEds$

Since the potential energy of the system is positive, therefor the electric potential energy also increases.

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4 years ago

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3 years ago

A uniform ladder of length l and mass m leans against a frictionless vertical wall, making an angle of 53° with the horizontal.

Phantasy [73]

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3 years ago