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Ivan
3 years ago
13

Six bags of soil are used to fill 5 flower pots. how much soil does each flower pot use? between what two whole numbers does the

answer lie?
each flower pot uses ? or ? bags of soil

so, 6 ÷ 5= ?

the answer is between the whole numbers ____ and ____.
Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0
The answer is between the numbers 1 and 2
andrew-mc [135]3 years ago
5 0
So Basically It's 5×6?
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51 is more than a number is -12. What is the number?
Ivenika [448]
The answer to 51 is more than a number is -12: is 43.
7 0
3 years ago
In the diagram, ΔGHJ ≅ ΔSTU.
Anna007 [38]

Step-by-step explanation:

angle J is also 67 deg since the triangle is an isosceles triangle

angle T is 67 deg since the 2 triangles are congruent

angle G = 180 - 2x67 = 46 deg

ST is 5cm

HJ is 3.7cm

3 0
1 year ago
Find the slope of a line parallel to the line through the given points. P(-2, 4), Q(6, -2) 4/3 3/4 -3/4
Galina-37 [17]

Answer:

slope = - \frac{3}{4}

Step-by-step explanation:

Parallel lines have equal slopes thus the slope of a parallel line will be equal to the slope of PQ

To calculate slope m use the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = P(- 2, 4) and (x₂, y₂ ) = Q(6, - 2)

m = \frac{-2-4}{6+2} = \frac{-6}{8} = - \frac{3}{4}

8 0
3 years ago
Read 2 more answers
Find the distance between the points given. (-3, 2) and (9, -3) A √37 B √61 C 13​
Kitty [74]

Answer:

\huge{ \fbox{ \sf{13 \: units}}}

Option C is correct.

Step-by-step explanation:

\star{ \sf{ \: Let \: the \: points \: be \: a \: and \: b}}

\star{ \sf{ \: let \: A(-3, 2) \: be \: (x1 \:, y1) \:  and  \: B(9, -3) \: be \: (x2 \:, y2) }}

\underline{ \sf{Finding \: the \: distance \: between \: the \: given \: points}} :

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{  \sqrt{ {(9 - ( - 3))}^{2} +  {( - 3 - 2)}^{2}  } }}

\mapsto{ \sf{ \sqrt{ {(9 + 3)}^{2}  +  {( - 3 - 2)}^{2} }}}

\mapsto{ \sf{ \sqrt{ {(12)}^{2}  +  {( - 5)}^{2} } }}

\mapsto{ \sf{ \sqrt{144 + 25}}}

\mapsto{ \sf{ \sqrt{169} }}

\mapsto{ \sf{ \sqrt{ {(13)}^{2} } }}

\mapsto{ \sf{ 13 \: units}}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

7 0
3 years ago
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                     = 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0
3 years ago
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