10 & 12
x = 1st consecutive even number
x + 2 = 2nd consecutive even number
x + x + 2 = 22
2x + 2 = 22
2x = 20
x = 10
x + 2 = 12
10 and 12 are the two consecutive even numbers
Answer:
<em>There are a few ways to solve systems of equations. </em>
- <em>There are a few ways to solve systems of equations. substitution</em>
- <em>There are a few ways to solve systems of equations. substitutionelimination</em>
- <em>There are a few ways to solve systems of equations. substitutionelimination </em><em>Graphically</em>
<em>If you are looking at a multiple choice question use the ordered pair to plug into the answer choices and whichever one balances out will be your answer. To assist you further I would need more information from the problem. </em>
Step-by-step explanation:
<em>hope</em><em> it</em><em> will</em><em> help</em><em> you</em><em> have</em><em> a</em><em> great</em><em> day</em><em> bye</em><em> and</em><em> Mark</em><em> brainlist</em><em> if</em><em> the</em><em> answer</em><em> is</em><em> correct</em><em> </em>
<em>
</em>
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Answer:
<em><u>x=-6, y=-2</u></em>, (As a point) (-6, -2).....The point form is not necessary unless you want to solve the system (of equations) by graphing.
Step-by-step explanation:
By substitution:
x-y=-4 By adding y on both sides,
x=y-4
Now you can substitute x for the expression (y-4)
Plug the (y-4) as x in the other equation.
So -2x+3y=6 becomes
-2(y-4)+3y=6
Now solve:
-2(y-4)+3y=6 distributes out to be
-2y+8+3y=6 Now combining like terms
y+8=6 Subtract 8 on both sides to isolate the variable
<u><em>y=-2</em></u>
Now plug the value -2 in where the y is in any equation (preferably the easier/less complicated one) and solve for x.
So x-y=-4 becomes
x-(-2)=-4
=x+2=-4
=<u><em>x=-6</em></u>
Answer:
3
Step-by-step explanation:
The value of "a" is the coefficient of x^2, so we know that is 2.
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<u>Solve for h</u>
Now, we have ...
2x^2 -8x +7 = 2(x -h)^2 +k
Expanding the right side gives us ...
= 2(x^2 -2hx +h^2) +k
= 2x^2 -4hx +2h^2 +k
Comparing x-terms, we see ...
-4hx = -8x
h = (-8x)/(-4x) = 2
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<u>Solve for k</u>
Now, we're left with ...
2h^2 +k = 7 = 2(2^2) +k = 8 +k
Subtracting 8 we find k to be ...
k = 7 -8 = -1
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And the sum of constants a, h, and k is ...
a +h +k = 2 +2 -1 = 3
The sum of the constants is 3.
