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Mice21 [21]
3 years ago
11

A population model for two species can describe either competition for resources (an increase in one species decreases the growt

h rate in the other) or cooperation for resources (an increase in one species increases the growth rate in the other) For the systems below identify the parameters as growth rates, carrying capacities, and measure of interactions between species. Determine if the species compete of cooperate r, = 31-334-5ry 50 y (a) Growth Rate Constants (b) Carrying Capacity Constants: (c) Interaction Constants: Note: Your answers must be numbers, (which may include 0). If there is more than one answer, separate your answers with commas (d) Choose One Note: You can eam partial credit on this probiem.
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
4 0

Answer:

8 im pretty sure......

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Which points are solutions to the linear inequality y < 0.5x + 2? Check all that apply.
marusya05 [52]
Are you given choices?
Plug in the x- and y-coordinates of the given points.
The ones that make the inequality true are solutions.
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3 years ago
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Which statement about an input/output table is true?
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The answer is c because the input values do not have to be consecutive, the output values can be decimals and fractions, and the output values are not always increasing as they go on, sometimes they decrease. for example, look at exponential decay and exponential growth. hope this helped (;
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Find f(x) and g(x) so the function can be expressed as y = f(g(x)). y = Two divided by x squared. + 3
kodGreya [7K]
Hello,

g(x)=x²+3
f(x)=2/x
so f(g(x))=f(x²+3)=2/(x²+3)

Explainations:

f(y)=2/y
f(4y)=2/(4y)
f(x²)=2/x²
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4 0
3 years ago
19. James has a desk job and would like to become more fit, so he purchases a
Neko [114]

Answer:

The correct answer is option (C)-0.245 = 2.160(0.205)

Step-by-step explanation:

Solution

Given that:

The slope = - 0.245

The size sample = n = 15

The standard error = 0.205

The confidence level = 95

The Significance level= α = (100- 95)% = 0.05

Now,

The freedom of degree = n-2 = 15 -2= 13

Thus,

the critical value = t* = 2.16

By applying Excel = [TINV (0.05, 13)]

The Margin of error is = t* (standard error)

=2.16 *0.205

= 0.4428

8 0
3 years ago
NO LINKS!! Please help me with this problem​
iogann1982 [59]

{\qquad\qquad\huge\underline{{\sf Answer}}}

The given figure shows a vertical hyperbola with its centre at origin, and as we observe the figure, we can conclude that :

Length of transverse axis is :

\qquad \sf  \dashrightarrow \: 2b = 12

\qquad \sf  \dashrightarrow \: b = 6

length of conjugate axis is :

\qquad \sf  \dashrightarrow \: 2a = 8

\qquad \sf  \dashrightarrow \: a = 4

Equation of hyperbola ~

\qquad \sf  \dashrightarrow \:    \cfrac{ {y}^{2} }{ {b}^{2} } - \cfrac{  {x}^{2} }{ {a}^{2} }  = 1

plug in the values ~

\qquad \sf  \dashrightarrow \:    \cfrac{ {y}^{2} }{ {6}^{2} } - \cfrac{  {x}^{2} }{ {4}^{2} }  = 1

\qquad \sf  \dashrightarrow \:    \cfrac{ {y}^{2} }{ {36}^{} } - \cfrac{  {x}^{2} }{ {16}^{} }  = 1

5 0
2 years ago
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