Answer:
Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.
Step-by-step explanation:
Given:
Population for rabbit obeys exponential law.
120 at 1990 and 240 1991 ...after 1 year time period
To Find:
After 9 year time period how many rabbits will be there.
Solution:
Exponential law goes on present value and various value and time period and defined as ,
let Y be present value Y0 previous year value and k exponential constant and t be time period.
So
Y=Y0e^(kt)
Here Y=240 ,Y0=120 t=1 year time period
So
240=120e^(k*1)
240/120=e^k
2=e^k
Now taking log on both side, [natural log]
ln(2)=ln(e^k)
ln(2)=kln(e)
k=ln(2)
k=0.6931
For t=9 year of time period
Y0=120, t=9 ,k=0.6931
Y=Y0e^(k*t)
Y=120*e^(0.6931*9)
=120e^6.2383
=61438.48
=61438 rabbits
Are their answer choices? There are infinitely many multiples of 5.
5, 10, 15, 20, 25, 30, 45, 50, 55, etc
Answer:
Step-by-step explanation:
Math requires a lot of thing and a procedure of steps for each topic. Yes I agree
Answer:
The common factors of 64 and 100 are 4, 2, 1, intersecting the two sets above. In the intersection factors of 64 ∩ factors of 100 the greatest element is 4. Therefore, the greatest common factor of 64 and 100 is 4.
Step-by-step explanation:
