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Alex17521 [72]
3 years ago
14

A parallel beam of light from a laser with a wavelength 450 nm, falls on a grating whose slits are 1.28 x 10^-4 cm apart. How fa

r (in cm) is the 1t order bright spot from the center of the pattern on a screen 3.4 m away?
Physics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

Y_1 = 1.195 m = 119.5 cm

Explanation:

For nth order bright fringe, the distance from the center of the pattern is given by :-

Y_n = \frac{n\lambda D}{d}.

Where,

n = order of nth  bright fringe. = 1

\lambda = wavelength of  given light  =  450 nm = 450*10-{9} m

D = distance between the screen and slits. =  3.4 m

and d = separation between the slits. = 1.28 *10^{-4} cm =1.28 *10^{-6} m

Y_1 = \frac{(1 *450 *10{-9} *3.4)}{(1.28*10{-6})}

Y_1 = 1.195 m = 119.5 cm

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Ahab has been sent to the shops by his mother. The shops are 1200 m from his
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Answer:

it will take him 200secs to run to the shops

(btw 200 seconds is 3minutes and 20secs)

Explanation:

distance = speed x time

time = distance / speed

1200 ÷ 6 = 200

time = 200seconds

hope this helps

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8 0
3 years ago
Which of the following is NOT true about the structure of the nucleus? a. The nucleus is filled with cytoplasm b. The nucleus ha
Cerrena [4.2K]

Answer:

A. The nucleaus is filled with cytoplasm OR d. The nucleus is by a double layer membrane.

Explanation:

b. and c. are true and I'm certain they are true

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3 0
3 years ago
How many photons strike the cd surface during the playing of a cd 69 minutes in length?
Reptile [31]

Answer:

Photons strike the CD n=1.624 x10^{18}

Explanation:

First of all, it is necessary to calculate the energy produced by a semiconductor laser for 69 minutes:

69minutes*\frac{60s}{1 minute}=4140s

E=0.1x10^{-3}w*4140s=0.414J

Next, it is possible to calculate the number of photons striking the CD surface during this time:

E=\frac{n*h*c}{l}

l=780x10^{-9}m long in CD

c=3x10^8 m/s light velocity

h=6.626x10^{-34} J*s

Solve to n'

n=\frac{E*l}{c*h}=\frac{0.414 J*780x10^{-9}m}{3x10^8m/s*6.626x10^{-34}}

n=1.624 x10^{18}

8 0
3 years ago
An aluminum rod and a nickel rod are both 5.00 m long at 20.0 degree Celsius. The temperature of each is raised to 70.0 degrees
vitfil [10]

Answer:

0.002925 m

Explanation:

Lt = LO(1 +α Δt ) here Lt is total length Lo is original length α is coefficient of linear expansion and Δt is change in temperature

<h2>for aluminium</h2>

α=25×10^-6

Lt = 5(1+25×10^-6×(70-20))

Lt = 5 (1+25×10^-6×50)

Lt = 5 ( 1+0.00125)

Lt = 5×1.00125

Lt =5.00625 m

<h2>for nickel </h2>

α=13.3×10^-6

Lt =5(1+13.3×10^-6×50)

Lt = 5(1+0.000665)

Lt =5.003325 m

hence difference in length =5.00625-5.003325

                                           = 0.002925 m

3 0
3 years ago
the internal energy of an object has two parts: internal potential energy of its molecules and the kinetic energy of those molec
BARSIC [14]
The most appropriate answer is B !! No heat flow as there is no difference in temp between them !!
8 0
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