Answer:
The coefficient of performance for the cycle is 2.33.
Explanation:
Given that,
Output energy 
Work done 
We need to calculate the coefficient of performance
Using formula of the coefficient of performance

We need to calculate the 

Put the value into the formula



Now put the value of
into the formula of COP


Hence, The coefficient of performance for the cycle is 2.33.
Regardless of the speed of the ball or its angle, once it has left the kickers foot it's acceleration is always g downward. -9.81m/s^2
Answer:
The acceleration of the ball as it rises to the top of its arc equals 9.807 meters per square second.
Explanation:
Let suppose that maximum height of the arc is so small in comparison with the radius of the Earth.
Since the ball is launched upwards, then the ball experiments a free-fall motion, that is, an uniform accelerated motion in which the element is accelerated by gravity. Then, the acceleration experimented by the motion remains constant at every instant and position.
Besides, the gravitational acceleration in the Earth and, in consequence, the acceleration of the ball as it rises to the top of its arc equals 9.807 meters per square second.
If you neglect air resistance, then you can solve for the horizontal distance using the formula:
dx=vixt
Where:
dx = horizontal distance
vix = initial horizontal velocity
t = time in flight
Now you can see that you have all the given you need.
vix= 2km/h
t = 0.25 hours
We use hours because you need the units to be the same. So just plug that in your equation and you will have your answer:
dx = vixt
=(2km/h)(0.25h)
=0.5km
This means that the answer to your question is B.