1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
suter [353]
3 years ago
14

Gravity is dependent on which of the two factors? mass and weight distance and weight mass and force mass and distance

Physics
2 answers:
andre [41]3 years ago
8 0
Gravity = m₁m₂G / r²

G constant
m mass
r distance
gtnhenbr [62]3 years ago
8 0
Gravity = Gm₁m₂ / r²

G = gravitational constant
m = mass of the body
r = distance between the bodies
You might be interested in
1) A boy drags a wooden crate with a mass of 20 kg, a distance of 12 m, across a rough level floor at a constant speed of 1.5 m/
mojhsa [17]

Answer: a) 49.560 and 21.13 b) i) 50 N, ii) 196 N iii) 196 N iv) 47.685 N

c) i) 594.72 ii) 0 iii) 0 iv) 0

d) 594.72

Explanation: question a)

The force is inclined at an angle of 25° to the horizontal

The horizontal component of force = 50 cos 25° = 49.560 N

The vertical component of force = 50 sin 30°= 21.130N

Question b)

i) according to the question applied force is 50 N

ii) if g = 9.8m/s², w=mg where m = mass of object = 20kg hence weight = 20* 9.8 = 196 N

iii) the normal force is the force the floor exerts on the body as a result of the weight of the object.

Normal reaction R = W = mg, we already deduced that w = mg, hence R = 196 N.

iv) according to newton's laws of motion

F - Fr = ma

F = applied force = horizontal component of force = 49.560 N.

We need to get the acceleration (a) by using Newton laws of motion before we can be able to compute the frictional force..

The body started from rest hence initial velocity u = 0

Final velocity v = 1.5m/s distance covered (s) = 12m

v ² = u² + 2as

But u = 0

v² = 2as

1.5² = 2(a) * 12

2.25 = 24a

a = 2.25/24 = 0.09735m/s²

From F - Fr = ma

49.560 - Fr = 20 * 0.09735

49.560 - Fr = 1.875

Fr = 49.560 - 1.875

Fr = 47.685 N

Question c)

i) The applied force = 49.560 N, distance covered = 12m

Work done = force * distance

Work done = 49.560 * 12

Work done = 594.72 J

ii) the weight of the object does not make the object move a distance, hence work done = 0 ( since distance covered is 0)

iii) the normal force is the same thing as the weight and they did not cover any distance hence work done is zero.

iv) the frictional force does not cover any distance, hence work done is zero.

Question d)

The total work done = work done by applied force + work done by weight + work done by normal reaction + work done by frictional force.

Total work done = 594.72 + 0 + 0 + 0 = 594.72 J

8 0
3 years ago
a) What is the average useful power output of a person who does6.00×10^6Jof useful work in 8.00 h? (b) Working at this rate, how
NARA [144]

Answer:

208.33 W

141.26626 seconds

Explanation:

E = Energy = 6\times 10^6\ J

t = Time taken = 8 h

m = Mass = 2000 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height of platform = 1.5 m

Power is obtained when we divide energy by time

P=\frac{E}{t}\\\Rightarrow P=\frac{6\times 10^6}{8\times 60\times 60}\\\Rightarrow P=208.33\ W

The average useful power output of the person is 208.33 W

The energy in the next part would be the potential energy

The time taken would be

t=\frac{E}{P}\\\Rightarrow t=\frac{mgh}{208.33}\\\Rightarrow t=\frac{2000\times 9.81\times 1.5}{208.33}\\\Rightarrow t=141.26626\ s

The time taken to lift the load is 141.26626 seconds

5 0
3 years ago
After observing the electric field in your trials above, where was the electric field the strongest? what was the direction of t
earnstyle [38]
<span>Answer: Answer is The direction of the electric field is always directed in the direction that a positive test charge would be pushed or pulled if placed in the space surrounding the source charge.</span>
8 0
3 years ago
ASTRONOMY !! PLS HELP!!
aleksandr82 [10.1K]

-- pick a planet from the table

-- take it's mass and radius from the table, and plug them into the big ugly formula above the table

-- do the arithmetic with your pencil or your calculator. The answer is the acceleration of gravity on the planet you picked. Write it down so you don't lose it.

-- do the same for the other 3 planets in the table

6 0
3 years ago
Is adequate health care are available to all
tankabanditka [31]

Explanation:

I think for anyone to answer this we need more info on what you want answered. The Sentence Itself doesn't Make Since To Me

6 0
2 years ago
Other questions:
  • A force of 300 N is used to stretch a horizontal spring with a 0.5 kg block. The length of spring is 0.25 m. The block is releas
    14·1 answer
  • Why is it very difficult for astronomers to find objects like planets and asteroids?
    11·1 answer
  • A wave travels a distance of 60cm in 3s. The distance blw successive crests of thd wave is 4cm. What is the frequency?
    9·1 answer
  • An engineer has the task of producing an aluminum alloy with a density of 3.0 grams per cubic centimeter. She comes up with the
    6·1 answer
  • Which FBD would represent a car moving right with a motor force of 250 N, and force of friction of 750N, a weight of 8500N and a
    5·1 answer
  • ? Why might the expejiment need to be repeated when the hypothesis
    14·1 answer
  • A student wants to draw a model of an atom. Which statement describes how to find the number of neutrons to include in the model
    9·1 answer
  • 1) A bowling has a mass of 5 kg and a speed of 8 m/s. What is its momentum?
    13·1 answer
  • A small car of mass 1200 kg traveling east at 60m/s collides at an intersection with a truck of mass 3000 kg that is traveling d
    10·2 answers
  • two charges experience exert a force of 1n on each other when they are 1m apart. what force will these charges experience if the
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!