Answer:
0.5mv^2=50, v=5, 25/2×m=50, m=50×2/25, So, the answer is 4
F = force applied to hold the weight of the bowling ball = weight of the bowling ball = 75 N
d = distance through which the bowling ball is moved horizontally = 10 meter
θ = angle between the force in vertically upward direction and displacement in horizontal direction = 90
W = work done on the bowling ball
work done on the bowling ball is given as
W = F d Cosθ
inserting the values
W = (75) (10) Cos90
W = (75) (10) (0)
W = 0 J
Answer:
x component 60.85 m
y component 101.031 m
Explanation:
We have given distance r = 118 km
Angle which makes from ground = 58.9°
(a) X component of distance is given by 
(b) Y component of distance is given by 
These are the x and y component of position vector
The resistance of the piece of wire is

where

is the resistivity of the copper

is the length of the piece of wire

is the cross sectional area of the wire
By substituting these values, we find the value of R:

Then, by using Ohm's law, we find the potential difference between the two points of the wire: