Let <em>v</em> be the dog's initial velocity. Then
(13.5 m/s)^2 - <em>v</em> ^2 = 2 (1.50 m/s^2) (49.3 m)
==> <em>v</em> ^2 = (13.5 m/s)^2 - 2 (1.50 m/s^2) (49.3 m)
==> <em>v</em> = √((13.5 m/s)^2 - 2 (1.50 m/s^2) (49.3 m))
==> <em>v</em> ≈ 5.86 m/s
Answer:
The answer to your question is Decrease
Answer:
B. right shoe
Explanation:
When the puck comes to a stop after it collides with the left shoe both their velocities becomes zero. This means that their relative velocities is zero as the linear momentum is conserved.
When the puck rebounds after it collides with the right shoe then the right shoe will also move as linear momentum is conserved.
For elastic collision
![m_{1}u_{1}+m_{2}u_{2}\ =m_{1}v_{1}+m_{2}v_{2}](https://tex.z-dn.net/?f=m_%7B1%7Du_%7B1%7D%2Bm_%7B2%7Du_%7B2%7D%5C%20%3Dm_%7B1%7Dv_%7B1%7D%2Bm_%7B2%7Dv_%7B2%7D)
Hence, the right shoe will have a greater speed after collision.
Answer:
lol
Explanation:
ok well Jesus considered himself and his disciples fishers of men, so i'd say he swam with the fishies on land everytime he had a mob of people listening lollllll
Answer:
Its speed decreases.
Explanation:
When light enters into water, its speed decreases (as well as its frequency). This is the reason why refraction (the bending of light when it changes media) occurs.
This can be proven mathematically.
Given that the refractive index of water is 4/3, we know that refractive index is the ratio of the speed of light in a vacuum to the speed of light in another medium.
Therefore,
4/3 = (speed of light in vacuum) / (speed of light in water)
Speed of light in a vacuum is 3 * 10^8. Hence,
Speed of light in water is:
v = (3 * 10^8) / (4/3)
v = 2.25 * 10^8 m/s
As we can see, the speed of light decreases in water.