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kozerog [31]
4 years ago
10

What does malleablity means

Physics
1 answer:
daser333 [38]4 years ago
3 0

Able to be hammered or pressed permanently out of shape without breaking or cracking.

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Sports car goes from a velocity of zero to a velocity of 12 m/s East in two seconds. What is the cars acceleration?
bogdanovich [222]

Answer:

6 m/sec

Explanation:

12/2=6

7 0
4 years ago
Which of these is a physical property?
Studentka2010 [4]
I think the answer is b. easy to digest.

C. and D. are chemical properties,
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3 years ago
Which of the following is an example of static friction?
boyakko [2]
Answer: C) Rubbing sticks together to create a fire.
6 0
4 years ago
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We observe that a small sample of material placed in a non-uniform magnetic field accelerates toward a region of stronger field.
Aleksandr [31]

Answer:

<em>C) It is either ferromagnetic or paramagnetic</em>

Explanation:

The complete question is given below

We observe that a small sample of material placed in a non-uniform magnetic field accelerates toward a region of stronger field. What can we say about the material?

A) It must be ferromagnetic.

B) It must be paramagnetic.

C) It is either ferromagnetic or paramagnetic.

D) It must be diamagnetic.

A ferromagnetic material will respond towards a magnetic field. They are those materials that are attracted to a magnet. Ferromagnetism is associated with our everyday magnets and is the strongest form of magnetism in nature. Iron and its alloys is very good example of a material that readily demonstrate ferromagnetism.

Paramagnetic materials are weakly attracted to an externally applied magnetic field. They usually accelerate towards an electric field, and form internal induced magnetic field in the direction of the external magnetic field.

The difference is that ferromagnetic materials can retain their magnetization when the externally applied magnetic field is removed, unlike paramagnetic materials that do not retain their magnetization.

In contrast, a diamagnetic material is repelled away from an externally applied magnetic field.

8 0
3 years ago
ASK YOUR TEACHER As an astronaut, you observe a small planet to be spherical. After landing on the planet, you set off, walking
Vsevolod [243]

Given Information:

circumference of planet = C = 25.7 km

height of release = h = 1.43 m

time = t = 30 s

Required Information:

Mass of planet = M = ?

Answer:

Mass of planet = M = 7.963×10¹⁴ kg

Explanation:

The mass of the planet can be found using Newton's law of gravitation,

g = GM/R²

M = gR²/G

Where g is the gravitational acceleration at the planet, R is the radius of the planet and G is the gravitational constant.

G = 6.6743×10⁻¹¹ m³/kg⋅s²

First we need to find R and g

The relation between circumference and radius is given by

C = 2πR

Where R is the radius of planet

25.7 = 2πR

R = 25.7/2π

R = 4.09 km

From the equations of motion we have,

h = ut + ½gt²

Where u is the initial speed which is zero, t is the time and h is the height of release.

Re-arrange the above equation for g

h = ½gt²

g = 2h/t²

g = (2*1.43)/(30)²

g = 0.003177 m/s²

Finally, the mass of the planet is

M = gR²/G

M = 0.003177*(4.09×10³)²/6.6743×10⁻¹¹

M = 7.963×10¹⁴ kg

Therefore, the mass of the given planet is 7.963×10¹⁴ kg

3 0
4 years ago
Read 2 more answers
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