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baherus [9]
3 years ago
13

Next to hydrogen and oxygen, what are the two most abundant elements in the ocean water?

Physics
2 answers:
Naddik [55]3 years ago
8 0
I believe it is D.

hope it helps Yami ^-^
OleMash [197]3 years ago
8 0
D the anwser id D because it clean the  water
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Physical Science AIS - AE 20-21-Kotal / Unit 2: Reactions and Radioactivity / The Environment
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Answer:19

Explanation:

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What is mechanics physics​
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Mechanics Physics is a area in physics dealing with motion of objects talking about when force applied to objects what happens whether displacement or changes of the position
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3 years ago
An 30-turn coil has square loops measuring 0.341 m along a side and a resistance of 3.61 Ω. It is placed in a magnetic field tha
Verdich [7]

Answer:

Thus, the induced current in the coil at t =1.73s is 9.98 A.

Explanation:

Faraday's law says

$\varepsilon = N \frac{d \Phi_B}{dt} $

where N is the number of turns and \Phi_B is the magnetic flux through the square coil:

Now,

N = 30

\theta = 37.5^o

A = (0.341m)^2= 0.11623m^2

B = 1.45t^3;

therefore,

$\varepsilon = N \frac{d \Phi_B}{dt}  = N\frac{d ( BA\:cos(\theta))}{dt}  = 30*\frac{d ( (1.45t^2)(0.1163)\:cos(37.5^o))}{dt}$

=30*(0.1163)\:cos(37.5^o)*1.45*\dfrac{d ( t^3)}{dt}  = 12.04t^2

\boxed{\varepsilon = 12.04t^2}

is the emf induced in the coil.

Now, the loop is connected to R = 3.61\Omega resistance; therefore, at t = 1.73s

\varepsilon = RI = 12.04t^2

RI = 12.04(1.73)^2

RI = 36.03

I = \dfrac{36.03}{3.61\Omega }

\boxed{I = 9.98A }

Thus, the current in the coil at t =1.73s is 9.98 A.

8 0
4 years ago
PLEASE HELP ME!!!! In your own words, what does Newton's first law mean to you?
julia-pushkina [17]

Answer:

His first law states that unless it is forced to change its state through external force, every object will remain stationary or move in a straight line at a constant speed. It is usually taken as the definition of inertia.

Explanation:

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4 years ago
What total energy (in J) is stored in the capacitors in the figure below (C1 = 0.900 µF, C2 = 16.0 µF) if 1.80 10-4 J is stored
Musya8 [376]

The total energy  stored in the capacitors is determined as  2.41 x 10⁻⁴ J.

<h3>What is the potential difference of the circuit?</h3>

The potential difference of the circuit is calculated as follows;

U = ¹/₂CV²

where;

  • C is capacitance of the capacitor
  • V is the potential difference

For a parallel circuit the voltage in the circuit is always the same.

The energy stored in 2.5 μf capacitor is known, hence the potential difference of the circuit is calculated as follows;

U = ¹/₂CV²

2U = CV²

V = √2U/C

V = √(2 x 1.8 x 10⁻⁴ / 2.5 x 10⁻⁶)

V = 12 V

The equivalent capacitance of C1 and C2 is calculated as follows;

1/C = 1/C₁ + 1/C₂

1/C = (1)/(0.9 x 10⁻⁶)  +  (1)/(16 x 10⁻⁶)

1/C = 1,173,611.11

C = 1/1,173,611.11

C = 8.52 x 10⁻⁷ C

The total capacitance of the circuit is calculated as follows;

Ct = 8.52 x 10⁻⁷ C   +   2.5 x 10⁻⁶ C

Ct = 3.35 x 10⁻⁶ C

The total energy of the circuit is calculated as follows;

U =  ¹/₂CtV²

U =  ¹/₂(3.35 x 10⁻⁶ )(12)²

U = 2.41 x 10⁻⁴ J

Learn more about energy stored in a capacitor here: brainly.com/question/14811408

#SPJ1

7 0
1 year ago
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