Answer:
The transition-metal have the highest oxidation number is Mo in Rb₃[MoO₃F₃]
Explanation:
Transition metals are metals that are found in the middle of the periodic table.
For the compounds:
Rb₃[MoO₃F₃]: Rb is an alkali metal that has a charge of +1. that means [MoO₃F₃] is -3. The oxyfluoride O₃F₃ has a charge of -9. That means the <em>Mo is +6</em>
K₄[Mn(CN)₆]: Potassium is +1, thus, the [Mn(CN)₆] is -4, As the CN is -1 and there are 6, the <em>Mn is +2</em>
Na[Ag(CN)₂]: As Na is +1, the [Ag(CN)₂] is -1. As CN are -1, the <em>Ag is +1</em>
K₂[PtCl₆]: Potassium is +1, the [PtCl₆] is -2, As the Cl are -1, the <em>Pt is +4</em>
[Co(NH₃)₄Cl₂]: The NH₃ are neutral, The Cl are -1, that means the <em>Co is +2.</em>
The transition-metal have the highest oxidation number is<em> Mo +6</em>
I hope it helps!
Answer:
38.4 atm.
Explanation:
- We can use the general law of ideal gas:<em> PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have different values of P and V:
<em>(P₁V₁) = (P₂V₂).</em>
P₁ = 3.0 atm, V₁ = 3200 L,
P₂ = ??? atm, V₂ = 250.0 L.
∴ P₂ = (P₁V₁)/(V₂) = (3.0 atm)(3200 L)/(250.0 L) = 38.4 atm.
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Answer:
223 g
Explanation:
Molar mass Fe = 55.845 g/mol
mass=molar mass* number of moles=55.845*4.00≈223 g
Answer:
how do i calculate that?tell me how and i will try to do your math
Answer:
Explanation:
Answer is B i got it right