The volume of 6.40 grams of O₂ gas at STP is 4.48L (option A). Details about volume can be found below.
<h3>How to calculate volume?</h3>
The volume of a gas can be calculated using the following formula:
p = m/v
Where;
- p = density
- m = mass
- v = volume
According to this question, the mass of O₂ gas at STP is 6.40 grams. The density of the gas at STP is 1.43 g/L.
1.43g/L = 6.4g/V
Volume of O2 = 6.4 ÷ 1.43 = 4.48L
Therefore, the volume of 6.40 grams of O₂ gas at STP is 4.48L.
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Answer:
(D) chlorine has a greater ionization energy than sodium
Explanation:
Sodium is the element of the group 1 and period 3 which means that the valence electronic configuration is
.
Chlorine is the element of the group 17 and period 3 which means that the valence electronic configuration is
.
Ionization energy is the minimum amount of energy which is required to knock out the loosely bound valence electron from the isolated gaseous atom.
<u>Thus, removal of one electron in sodium is easy as it will gain noble gas configuration and become stable. But this case does not exist in chlorine and hence, chlorine has a greater ionization energy than sodium.</u>
So,
Sodium is much more apt to exist as a cation than chlorine because chlorine has a greater ionization energy than sodium.
<span>This is a 2 step dissociation reaction. But to find \(\large K_a = \frac{[prodcuts]}{[reactants]}\)</span>
Answer:
- <u><em>Sodium fluoride</em></u>
Explanation:
A <em>solution </em>is constituted by two parts: the solute and the solvent (there may be more than 1 solute and more than 1 solvent, but that is not the key of the answer).
<em>Solute</em> is the substace that is dissolved and it is in less amount than the solvent.
<em>Solvent</em> is the substance that can dissolve the solute and it is a greater amount than the solute.
In the given solution:
- <em>sodium fluoride</em>, <em>85.0 mL</em>, is the solute,
- <em>water</em>, <em>350.0 mL</em> is the solvent, and
- the mixture of both substances is the solution.