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dsp73
3 years ago
9

Calcula el %m/v de alcohol en una mezcla utilizada para la desinfección de manos formada por: 15 ml de agua (densidad=1g/ml), 10

5 g de etanol (densidad: 0,798 g/ml) y 4,5 gramos de jabón líquido (densidad= 1,5 g/ml)
Chemistry
1 answer:
mr Goodwill [35]3 years ago
3 0

Answer:

%m/v =70%

Explanation:

El %m/v es una unidad de concentración que se define como cien veces la división entre la masa de una sustancia (En gramos) y el volumen total en el que esta sustancia se encuentra (en mL).

En el problema, debemos hallar la masa de etanol (Alcohol) y el volumen total de la solución.

<em>Masa alcohol: </em>

Ya te la dan en el problema: 105g

<em>Volumen solución:</em>

Volumen agua: 15mL

Volumen etanol: 105g × (1mL / 0.798g) = 131mL

Volumen Jabón líquido: 4.5g × (1mL / 1.5g) = 3mL

Volumen: 15mL + 131mL + 3mL

149mL

Así, el %m/v de alcohol en la solución es:

%m/v = (105g / 149mL) × 100

<h3>%m/v =70%</h3>

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15. Ammonium nitrate, NH4NO3, and aluminum powder react explosively producing nitrogen gas, water vapor and aluminum oxide. Writ
Lunna [17]

Answer:

2Al_(_S_) ~+~3NH_4NO_3_(_a_q_) ->3N_2_(_g_) ~+~6H_2O_(_g_) ~+~Al_2O_3_(_S_)

Entalpy=-2861.9~KJ

Explanation:

In this case, we have to start with the <u>reagents</u>:

Al~+~NH_4NO_3

The compounds given by the problem are:

-) <u>Nitrogen gas</u> =  N_2

-) <u>Water vapor</u>  =  H_2O

-) <u>Aluminum oxide</u> =  Al_2O_3

Now, we can put the products in the <u>reaction</u>:

Al_(_S_) ~+~NH_4NO_3_(_aq_) ->N_2_(_g_) ~+~H_2O_(_g_) ~+~Al_2O_3_(_S_)

When we <u>balance</u> the reaction we will obtain:

2Al_(_S_) ~+~3NH_4NO_3_(_a_q_) ->3N_2_(_g_) ~+~6H_2O_(_g_) ~+~Al_2O_3_(_S_)

Now, for the enthalpy change, we have to find the <u>standard enthalpy values</u>:

Al_(_S_)=0~KJ/mol

NH_4NO_3_(_a_q_)=-132.0~KJ/mol

N_2_(_g_)=0~KJ/mol

H_2O_(_g_)=~-~241.8~KJ/mol

Al_2O_3_(_S_)=~-~1675.7~KJ/mol

With this in mind, if we <u>multiply</u> the number of moles (in the balanced reaction) by the standard enthalpy value,  we can calculate the energy of the <u>reagents</u>:

(0*2)~+~(-132*3)=~-396~KJ

And the <u>products</u>:

(0*3)~+~(-241.8*6)~+~(-1675.7*1)=-3125.9~KJ

Finally, for the total enthalpy we have to <u>subtract</u> products by reagents :

(-3125.9~KJ)-(-396~KJ)=-2729.9~KJ

I hope it helps!

8 0
3 years ago
45.5 g of ice is heated from -25 degrees celsius to 150 degrees celcius. Calculate the total amount of heat required for the ent
tino4ka555 [31]

Answer:

Q = 16163.88 Joules

Explanation:

Given the following data;

Initial temperature, T1 = -25°C

Final temperature, T2 = 150°C

Mass = 45.5 g

Specific heat capacity of ice = 2.03 J/g°C

To find the quantity of heat required;

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 150 - (-25)

dt = 150 + 25

dt = 175°C

Substituting into the formula, we have;

Q = 45.5 * 2.03 * 175

Q = 16163.88 Joules

4 0
2 years ago
Molecules can be composed of plzzzzzzzzzzzz help me fast im giving 89 pts
exis [7]

Molecules made up of two or more elements are called compounds. Water, calcium oxide, and glucose are molecules that compound.

8 0
3 years ago
The photo shows a clay pot being made on a spinning potter's wheel. What
sineoko [7]

Answer:B

Explanation:

7 0
2 years ago
Can Magnesium hydroxide be used as the base for this titration? Why or why not? 5. Describe the procedure that you will follow t
kvasek [131]

Explanation:

A.

Yes

B.

2KHP + Mg(OH)2 = 2KOH + Mg(HP)2

KHP is an acidic salt which reacts with Mg(OH)2 which is a base via double displacement/decomposition reaction.

C.

• One approach is to prepare the solution volumetrically using KHP crystals.

• Preparing 1 liter of 0.1 M KHP you would add 0.1 moles of KHP

Molar mass of KHP(C8H5KO4)

= (12*8) + (5*1) + 39 + (16*4)

= 204 g/mol

Number of moles = mass/molar mass

= 20.4/204

= 0.1 mol.

• This is added to a 1 liter volumetric flask, add deionized water until near the fill line, stopper and mix

D.

Number of moles = molar concentration * volume

= 0.025 * 0.100

= 0.0025 mol

Equation for the reaction:

Ba(OH)2 + 2KHP --> Ba(KP)2 + 2H2O

1 mole of Ba(OH)2 reacted with 2 moles of KHP. By stoichiometry,

Number of moles of Ba(OH)2 = 0.0025/2

= 0.00125 mol.

Molarity = number of moles/volume

= 0.00125/0.01

= 0.125 M of Ba(OH)2.

4 0
2 years ago
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