Answer:
1. NO and Br₂
2. 77
3. 8.8
Explanation:
Let's consider the following reaction.
2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)
The equilibrium constant for this reaction is:
1. At this temperature does the equilibrium favor NO and Br₂, or does it favor NOBr?
Since Kc₁ < 1, the reactants are favored, that is, NO and Br₂.
2. Calculate Kc for 2 NOBr(g) ⇄ 2 NO(g) + Br₂(g)
The equilibrium constant is:
3. Calculate Kc for NOBr(g) ⇄ NO(g) + 1/2 Br₂(g)
The equilibrium constant is:
Answer:
This is the answer but I'm sure from all answers. I hope my answer help you.
The question is incomplete. The image showing the compound and the options in the questions is attached.
Answer:
B
Explanation:
If we closely examine the structure of the compound given in the question, we will notice that the reaction must involve the substitution of the hydroxyl group by chlorine in the parent molecule.
This occurs when the -OH group combines with H^+ to form -OH2^+ which is a good leaving group.
Compound B is formed because, when -OH2^+ leaves, a carbocation is created. This carbocation is stabilized by the alkyl groups attached to the carbon atom bearing the leaving group by +I inductive effect. This carbon atom bearing the leaving group is a tertiary carbon atom thus it forms a more stable carbocation. Hence the product formed.
