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WARRIOR [948]
2 years ago
7

In △ABC, m∠A=27°, c=14, and m∠B=25°. Find a to the nearest tenth.

Mathematics
1 answer:
Alenkinab [10]2 years ago
3 0

Answer:

8.1

Step-by-step explanation:

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Need help with number 50 plz
dmitriy555 [2]

Answer:

16 spoonfuls

Step-by-step explanation:

Round off the 1 1/8 oz spoon capacity to 1 oz.  Then divide 16 oz by 1 oz, obtaining the estimate 16 spoonfuls.

7 0
3 years ago
Question 15 please. I missed class cause of testing
amid [387]
You would first calculate the price per pound and then use that to calculate the correct price of each bag.
7 0
3 years ago
What is the approximate circumference of a circle with a diameter of 56 cm? (Use π = 3.14.) A. 351.68 cm B. 175.84 cm C. 87.92 c
laiz [17]
The answer to your question is 175.84 bc C=2(pi)r and if you plug in the numbers it equals 175.84... B   hope that helped :)
3 0
3 years ago
random sample has been taken from a normal population and two confidence intervals constructed using exactly the same data. The
Zepler [3.9K]

The sample mean of the random sample is 50

The margin of error (E) is the amount of error allowed in the random sample.

The confidence interval (CI) is given by:

CI = μ ± E = (μ - E, μ + E)

Given a confidence interval of (38.02, 61.98), hence:

μ - E = 38.02     (1)

μ + E = 61.98     (2)

Hence solving equations 1 and 2 simultaneously gives:

μ = 50, E = 11.98

Hence the sample mean of the random sample is 50

Find out more at: brainly.com/question/24131141

5 0
2 years ago
Simplify the quotient: y= 2x^2+10x-28/x^2-49 divided by 2x-4/x+7
devlian [24]

\textit{difference of squares} \\\\ (a-b)(a+b) = a^2-b^2 \\\\[-0.35em] ~\dotfill\\\\ \cfrac{2x^2+10x-28}{x^2-49}\div \cfrac{2x-4}{x+7}\implies \cfrac{2x^2+10x-28}{x^2-49}\cdot \cfrac{x+7}{2x-4} \\\\\\ \cfrac{2(x^2+5x-14)}{\underset{\textit{differenc of squares}}{x^2-7^2}}\cdot \cfrac{x+7}{2x-4}\implies \cfrac{2(x^2+5x-14)}{(x-7)~~\begin{matrix} (x+7) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot \cfrac{~~\begin{matrix} x+7 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{2(x-2)}

\cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(x^2+5x-14)}{x-7}\cdot \cfrac{1}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(x-2)}\implies \cfrac{x^2+5x-14}{x-7}\cdot \cfrac{1}{x-2} \\\\\\ \cfrac{~~\begin{matrix} (x-2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(x+7)}{x-7}\cdot \cfrac{1}{~~\begin{matrix} x-2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\implies \cfrac{x+7}{x-7}=y

4 0
2 years ago
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