A force of 45 newtons is applied on an object, moving it 12 meters away in the same direction as the force. What is the magnitud
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Answer:
Acceleration of the meteorite,
Explanation:
It is given that,
A Meteorite after striking struck a car, v = 0
Initial speed of the Meteorite, u = 130 m/s
Distance covered by Meteorite, s = 22 cm = 0.22 m
We need to find the magnitude of its deceleration. It can be calculated using the third equation of motion as :
So, the deceleration of the Meteorite is . Hence, this is the required solution.