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Sloan [31]
2 years ago
11

A hockey puck slides 55.0 m along the length of the rink in just 1.25 s. The slight friction between the puck and the ice provid

es a uniform acceleration. If the puck's final speed is 43.2 m/s, what is its initial speed? 31.4 m/s?​
Physics
1 answer:
topjm [15]2 years ago
3 0

Answer:

44.8 m/s

Explanation:

Use the Initial Speed Formula:

InS = 2(d/t) - Final Speed

InS = 2(55/1,25) - 43.2

InS = 2.44 - 43,2

InS = 88 - 43,2

InS = 44.8 m/s

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A device consisting of four heavy balls connected by low-mass rods is free to rotate about an axle. It is initially not spinning
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The angular speed of the device is 1.03 rad/s.

<h3>What is the conservation of angular momentum?</h3>

A spinning system's ability to conserve angular momentum ensures that its spin will not change until it is subjected to an external torque; to put it another way, the rotation's speed will not change as long as the net torque is zero.

Using the conservation of angular momentum

L_{i}=L_{f}

Here,  = the system's angular momentum before the collision

L_{i} = 0 + mv

= (0.005)(450)(0.752)

= 1.692 kgm²/s

The moment of inertia of the system is given by

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= 2[(1.2)(0.8)² +(0.5)(0.3)²]+0.005(0.8)²

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To know more about the conservation of angular momentum, visit:

brainly.com/question/1597483

#SPJ1

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