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Klio2033 [76]
3 years ago
12

Which of the following best describes hair? O Hair is made of mostly tightly packed living cells Hair does not help control body

temperature. O Hair growth occurs in the hair follicle O Hair grows at 2.5mm a month.​
Chemistry
1 answer:
Elodia [21]3 years ago
5 0

Answer:

I think its the first one becuase it really descripes

Explanation:

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Gold melts at 1064 c. Melting point is a ___.
Tasya [4]

Physical property .      


8 0
3 years ago
Read 2 more answers
Why aint no won answering my question on go my latest questions if u want to help :(
77julia77 [94]
Can u send me the link ? Sorry tho but I don’t know how to go to ur questions :(
3 0
3 years ago
Chlorine is used to make bleach solutions containing 5.25% NaClO (by mass). Assuming 100% yield in the reaction producing NaClO
Archy [21]

To make 1000. L of bleach solution 1.69×10⁴ L of Cl₂(g) at STP will be needed .

<h3>What is Balanced chemical equation?</h3>

A balance chemical equation is an equation that contain same number of atoms as well as of each element on each side of reaction.

<h3>What is Density?</h3>

It is ratio of mass to the volume.

Density= \frac{Mass}{Volume}

Now,

   The balanced chemical equation of preparing bleach from chlorine is as follow:

Cl₂(g) + 2NaOH(aq) → NaClO(aq) + NaCl(aq) + H₂O(l)

Now,

  To calculate the Moles of NaClO in 1000L solution, first calculate it's mass.

Mass of NaClO = Density × Volume

                         =  1.07\frac{g}{ml} × 1000L × \frac{1000mL}{1L} ×\frac{5.25}{100}

                         = 56175g

Now, we have to calculate moles of NaClO

Hence,

  Moles of NaClO = \frac{amount of NaClO}{molar mass of NaClO}

                              =  \frac{56175g}{74.44\frac{g}{mol} }

                              = 754.63 mol

Now,

According to the reaction number of moles of Cl₂ is equal to the number of moles of NaClO.

Hence,

  moles of Cl₂ = 754.63 mol

Now , in order to calculate litres of Cl₂ at STP,

 We know that

 1 mol Cl₂ = 22.4 L of Cl₂

 754.63 mol of Cl₂ = 754.63 mol × 22.4 L

                               =   1.69×10⁴ L of Cl₂

Thus from the above conclusion we can say that , to make 1000. L of bleach solution 1.69×10⁴ L of Cl₂(g) at STP will be needed .

Learn more about Balanced Chemical Equation here:brainly.com/question/27135494

#SPJ4

       

5 0
2 years ago
The reducing agent in this catalytic hydrogenation reaction was molecular hydrogen (H2), which was produced in situ (in the reac
creativ13 [48]

Answer:

a)  After the balloon inflated after 440 uL of dropwise due to the reaction of 1-Decene and the solution in the conical vial. b) 4NaBH_{4} + 2HCl + 7H_{2}O ⇒ 16H_{2(g)}+ 2NaCl + Na_{2}B_{4}O_{7} c) No H_{2} was not the limiting reactant.

Explanation:

Generally, hydrogenation is the chemical reaction between a compound or element and molecular hydrogen in the presence of catalysts such as platinum.

a) After the balloon inflated after 440 uL of dropwise 1-Decene solution was added due to the reaction between 1-Decene and the solution in the conical vial.

b)  4NaBH_{4} + 2HCl + 7H_{2}O ⇒ 16H_{2(g)}+ 2NaCl + Na_{2}B_{4}O_{7}

c) H_{2} was not the limiting reactant based on the mol to mol ratio of H_{2} and decane which is 1:1. Therefore, if 0.8 mol of decane was produced then 0.8 mol of H_{2} would also be produced.

4 0
3 years ago
Round off 35.65 to three significant figures.<br><br><br> help
Nataliya [291]
The answer is B 35.7
3 0
3 years ago
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